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April 12th, 2018, 01:17 PM   #11
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Originally Posted by Micrm@ss View Post
You got to respect your units!
Gospel
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April 12th, 2018, 05:17 PM   #12
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.....Therefore the % of the new liquid which is milk is $\displaystyle \dfrac{M}{12}$. You said that the % of milk went down by 15% so ...

$\displaystyle \dfrac{M}{10}-\dfrac{M}{12}=0.15$ and $\displaystyle M=9$.

How can you be so sure that difference between $\displaystyle \dfrac{M}{10}$ and $\displaystyle \dfrac{M}{12}$ is 0.15 ?

question reads concentration of milk is reduced by 15% they never mention about difference or subtraction in any form.

This is another possibility of final equation: 0.15 + $\displaystyle \dfrac{M}{10}$ = $\displaystyle \dfrac{M}{12}$


This is another possibility of final equation: $\dfrac{\dfrac{M}{12}}{\dfrac{M}{10}}$ = 0.15

Question used the word "added" so why not this equation: $\dfrac{M}{10} + \dfrac{M}{12}$ = 0.15 ?

Out of so many possibilities why you choose $\displaystyle \dfrac{M}{10}-\dfrac{M}{12}=0.15$ ?

Last edited by Ganesh Ujwal; April 12th, 2018 at 06:03 PM.
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April 12th, 2018, 05:58 PM   #13
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Originally Posted by Ganesh Ujwal View Post
question reads concentration of milk is reduced by 15% they never mention about difference or subtraction in any form.
If you have 7 liters and you reduce the amount by 2 liters, how many liters will you have?
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April 12th, 2018, 06:02 PM   #14
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Originally Posted by mrtwhs View Post
If you have 7 liters and you reduce the amount by 2 liters, how many liters will you have?
5 . you are asking simple question but my question is complex one and also I am not dumb.
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April 12th, 2018, 07:23 PM   #15
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In a milk solution of 10 lit, 2 lit of water is added thereby the concentration of milk is reduced by 15%. What is the quantity of milk in the solution?

I tried:

Concentration - Water added - Milk:

100 - 0 - 10 liter

85 - 0 - ?

$\displaystyle \frac {85\times10}{100} = 8.5$

But Answer is 9 litres. Please tell how to solve this problem?
Did YOU read your own question? The answer is clearly 10 liters.
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April 12th, 2018, 07:26 PM   #16
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Did YOU ..... liters.
Feel free to ignore my posts next time onwards.
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April 12th, 2018, 11:08 PM   #17
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I find the solution myself:

So, the initial concentration of milk is $\dfrac {x}{10}$. It is $\dfrac {15}{100}$ more than the new concentration $\dfrac{x}{12}$ => $\dfrac{x}{10}- \dfrac{15}{100} = \dfrac {x}{12}$. Solving this equation x equals 9 liters.
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