My Math Forum What is the quantity of milk in the solution?

 Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion

April 12th, 2018, 01:17 PM   #11
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Quote:
 Originally Posted by Micrm@ss You got to respect your units!
Gospel

April 12th, 2018, 05:17 PM   #12
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 Originally Posted by mrtwhs .....Therefore the % of the new liquid which is milk is $\displaystyle \dfrac{M}{12}$. You said that the % of milk went down by 15% so ... $\displaystyle \dfrac{M}{10}-\dfrac{M}{12}=0.15$ and $\displaystyle M=9$.

How can you be so sure that difference between $\displaystyle \dfrac{M}{10}$ and $\displaystyle \dfrac{M}{12}$ is 0.15 ?

question reads concentration of milk is reduced by 15% they never mention about difference or subtraction in any form.

This is another possibility of final equation: 0.15 + $\displaystyle \dfrac{M}{10}$ = $\displaystyle \dfrac{M}{12}$

This is another possibility of final equation: $\dfrac{\dfrac{M}{12}}{\dfrac{M}{10}}$ = 0.15

Question used the word "added" so why not this equation: $\dfrac{M}{10} + \dfrac{M}{12}$ = 0.15 ?

Out of so many possibilities why you choose $\displaystyle \dfrac{M}{10}-\dfrac{M}{12}=0.15$ ?

Last edited by Ganesh Ujwal; April 12th, 2018 at 06:03 PM.

April 12th, 2018, 05:58 PM   #13
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Quote:
 Originally Posted by Ganesh Ujwal question reads concentration of milk is reduced by 15% they never mention about difference or subtraction in any form.
If you have 7 liters and you reduce the amount by 2 liters, how many liters will you have?

April 12th, 2018, 06:02 PM   #14
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Quote:
 Originally Posted by mrtwhs If you have 7 liters and you reduce the amount by 2 liters, how many liters will you have?
5 . you are asking simple question but my question is complex one and also I am not dumb.

April 12th, 2018, 07:23 PM   #15
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Quote:
 Originally Posted by Ganesh Ujwal In a milk solution of 10 lit, 2 lit of water is added thereby the concentration of milk is reduced by 15%. What is the quantity of milk in the solution? I tried: Concentration - Water added - Milk: 100 - 0 - 10 liter 85 - 0 - ? $\displaystyle \frac {85\times10}{100} = 8.5$ But Answer is 9 litres. Please tell how to solve this problem?

April 12th, 2018, 07:26 PM   #16
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Quote:
 Originally Posted by Jomo Did YOU ..... liters.
Feel free to ignore my posts next time onwards.

 April 12th, 2018, 11:08 PM #17 Senior Member   Joined: Aug 2014 From: India Posts: 310 Thanks: 1 I find the solution myself: So, the initial concentration of milk is $\dfrac {x}{10}$. It is $\dfrac {15}{100}$ more than the new concentration $\dfrac{x}{12}$ => $\dfrac{x}{10}- \dfrac{15}{100} = \dfrac {x}{12}$. Solving this equation x equals 9 liters.

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