
Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion 
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April 12th, 2018, 02:17 PM  #11 
Senior Member Joined: Sep 2015 From: USA Posts: 2,203 Thanks: 1157  
April 12th, 2018, 06:17 PM  #12  
Senior Member Joined: Aug 2014 From: India Posts: 343 Thanks: 1  Quote:
How can you be so sure that difference between $\displaystyle \dfrac{M}{10}$ and $\displaystyle \dfrac{M}{12}$ is 0.15 ? question reads concentration of milk is reduced by 15% they never mention about difference or subtraction in any form. This is another possibility of final equation: 0.15 + $\displaystyle \dfrac{M}{10}$ = $\displaystyle \dfrac{M}{12}$ This is another possibility of final equation: $\dfrac{\dfrac{M}{12}}{\dfrac{M}{10}}$ = 0.15 Question used the word "added" so why not this equation: $\dfrac{M}{10} + \dfrac{M}{12}$ = 0.15 ? Out of so many possibilities why you choose $\displaystyle \dfrac{M}{10}\dfrac{M}{12}=0.15$ ? Last edited by Ganesh Ujwal; April 12th, 2018 at 07:03 PM.  
April 12th, 2018, 06:58 PM  #13 
Senior Member Joined: Feb 2010 Posts: 697 Thanks: 135  
April 12th, 2018, 07:02 PM  #14 
Senior Member Joined: Aug 2014 From: India Posts: 343 Thanks: 1  
April 12th, 2018, 08:23 PM  #15  
Newbie Joined: Nov 2013 Posts: 26 Thanks: 8  Quote:
 
April 12th, 2018, 08:26 PM  #16 
Senior Member Joined: Aug 2014 From: India Posts: 343 Thanks: 1  
April 13th, 2018, 12:08 AM  #17 
Senior Member Joined: Aug 2014 From: India Posts: 343 Thanks: 1 
I find the solution myself: So, the initial concentration of milk is $\dfrac {x}{10}$. It is $\dfrac {15}{100}$ more than the new concentration $\dfrac{x}{12}$ => $\dfrac{x}{10} \dfrac{15}{100} = \dfrac {x}{12}$. Solving this equation x equals 9 liters. 

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milk, quantity, solution 
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