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April 11th, 2018, 07:03 PM  #1 
Senior Member Joined: Aug 2014 From: India Posts: 310 Thanks: 1  Find the age of A 5 years hence.
The Present average age of 4 persons A, B , C and D is 37 years. A's age is equal to the average of B and C together and B's age is equal to the average age of A and C together. If the present age of C is 44 years. Find the age of A 5 years hence. My try: $\displaystyle A = \frac {B+C}{2}$ $\displaystyle B = \frac {C+D}{2}$ $\displaystyle \frac {\frac{\frac{C+D}{2} + C}{2} +\frac {C+D}{2} +C + D}{4}$ $\displaystyle \frac {\frac {44+D}{2} +44 + 3(44+D)}{2}$ $\displaystyle 4(44+D) + 88 = 37\times4$ I tried so much. But my approach is right or wrong? if wrong, please tell the correct procedure. Last edited by Ganesh Ujwal; April 11th, 2018 at 07:15 PM. 
April 12th, 2018, 03:37 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 19,511 Thanks: 1743 
If your opening paragraph is correct, you know that (A + B + C + D)/4 = 37, A = (B + C)/2, B = (A + C)/2, and C = 44, and the solution of those equations is (A, B, C, D) = (44, 44, 44, 16). This means that A's age 5 years hence is 49. If you intended that B's age equals the average age of C and D together, you know (A + B + C + D)/4 = 37, A = (B + C)/2, B = (C + D)/2, and C = 44, and the solution of those equations is (A, B, C, D) = (40, 36, 44, 28). This would mean that A's age 5 years hence is 45. 

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