
Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion 
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February 17th, 2018, 12:31 AM  #1 
Newbie Joined: Feb 2018 From: Montana Posts: 2 Thanks: 0  Word Problem Help.
I am having trouble solving this word problem. Could somebody please take me through he steps. I think I am hung up on the Kilobyte to pages conversion. One kilobyte of computer memory will hold about 2/3 of a page of typical text (without formatting). A typical book has about 400 pages. Can the 9gig flash drive I carry in my pocket hold tens, hundreds, or thousands of such books? 
February 17th, 2018, 12:50 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 19,723 Thanks: 1807 
As 600 kilobytes of computer memory would hold 600 Ã— 2/3 = 400 pages, which corresponds to one typical book, you need to divide the flash drive's capacity by 600 kilobytes. If the flash drive's capacity is 9 gigabytes, that calculation gives 15 thousand.

February 17th, 2018, 12:51 PM  #3 
Newbie Joined: Feb 2018 From: Montana Posts: 2 Thanks: 0 
Thanks for the reply skipjack. I am not grasping what steps we take to come up with the figure 600kb to plug into the other numbers using only the information provided. 600? Ã— 2/3 = 400 pages. 
February 17th, 2018, 07:35 PM  #4 
Global Moderator Joined: Dec 2006 Posts: 19,723 Thanks: 1807 
I divided 400 by 2/3 to get 600, so I knew that 600 Ã— 2/3 (pages) would equal 400 pages.

February 20th, 2018, 04:49 AM  #5 
Math Team Joined: Jan 2015 From: Alabama Posts: 3,261 Thanks: 894 
Notice that the original problem said that there were 400 pages and the memory could hold 2/3 page per kilobyte or "$\displaystyle \frac{page}{kilobyte}$". To cancel "page" and get the number of "kilobytes" 400 pages will hold, we need to multiply "page" by "$\displaystyle \frac{kilobyte}{page}$" which is the same as dividing by "$\displaystyle \frac{page}{kilobyte}$". That is how we know we must divide "400 pages" by "2/3 page per kilobyte". Last edited by Country Boy; February 20th, 2018 at 04:51 AM. 

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