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August 26th, 2017, 11:57 AM   #11
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Okay, c ya in 4^4 / 4 minutes then
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August 26th, 2017, 10:13 PM   #12
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Here is one more,
If A=1, B=2, C=3........Z=26

4 + 4 = FOUR + 4 = ( F + O + U + R ) + 4 = ( 6 + 15 + 21 + 18 ) + 4 = 60 + 4 = 64
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August 27th, 2017, 03:16 PM   #13
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Originally Posted by raul21 View Post
I have no patience.

$\displaystyle \sqrt{\sqrt{\sqrt{4^{4!}}}}$
Sorry guys, I'm doing this to explain it to people on another forum. I can't edit.

So, we have

$\displaystyle \sqrt{\sqrt{\sqrt{4^{4!}}}} = \sqrt{\sqrt{\sqrt{4^{24}}}} =

\sqrt{\sqrt{\sqrt{4^{12 \times 2}}}} = \sqrt{\sqrt{\sqrt{\left(4^{12}\right)^{2}}}} = \sqrt{\sqrt{4^{12}}} = \sqrt{\sqrt{4^{6 \times 2}}} = \sqrt{\sqrt{\left(4^6\right)^{2}}} =
\sqrt{4^{6}} = \sqrt{4^{3 \times 2}} = \sqrt{\left(4^3\right)^{2}} =
4^{3} = 4 \times 4 \times 4 = 16 \times 4 = 64.$
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Last edited by skipjack; August 27th, 2017 at 05:24 PM.
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August 27th, 2017, 05:59 PM   #14
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$\displaystyle \sqrt{4^{\Gamma(4)}}=64$
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