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July 1st, 2017, 05:52 AM   #1
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Problem with logs

I'm trying to solve this problem which I thought was easy:

log5-2log2+3/2log16

which I thought should be: log 5/2^2 + log16^2/3

so: log 1.25 x log 16^2/3


not sure how to work this out -help apprciated
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July 1st, 2017, 06:26 AM   #2
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log5 - 2log2 + (3/2)log16 = log5 - 2log2 + 6log2 = log5 + 4log2 = log80
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July 1st, 2017, 06:54 AM   #3
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Thanks

Forgot that 3/2log16 could become 6log2, so it equals 3/2log 2^4 and you then multiply the exponent in front by 4.

Have I explained that correctly? Thanks
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July 1st, 2017, 07:15 AM   #4
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3/2log16 = 3/2log(2^4) = (3/2)*4log2 = 6log2

(An explanation in words, if needed, should clearly explain the above steps.)
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