My Math Forum Problem with logs

 Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion

 July 1st, 2017, 05:52 AM #1 Newbie   Joined: Jan 2017 From: Britain Posts: 18 Thanks: 0 Problem with logs I'm trying to solve this problem which I thought was easy: log5-2log2+3/2log16 which I thought should be: log 5/2^2 + log16^2/3 so: log 1.25 x log 16^2/3 not sure how to work this out -help apprciated
 July 1st, 2017, 06:26 AM #2 Global Moderator   Joined: Dec 2006 Posts: 19,191 Thanks: 1649 log5 - 2log2 + (3/2)log16 = log5 - 2log2 + 6log2 = log5 + 4log2 = log80
 July 1st, 2017, 06:54 AM #3 Newbie   Joined: Jan 2017 From: Britain Posts: 18 Thanks: 0 Thanks Forgot that 3/2log16 could become 6log2, so it equals 3/2log 2^4 and you then multiply the exponent in front by 4. Have I explained that correctly? Thanks
 July 1st, 2017, 07:15 AM #4 Global Moderator   Joined: Dec 2006 Posts: 19,191 Thanks: 1649 3/2log16 = 3/2log(2^4) = (3/2)*4log2 = 6log2 (An explanation in words, if needed, should clearly explain the above steps.)

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### 3/2log16-6log2

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