
Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion 
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July 1st, 2017, 05:52 AM  #1 
Newbie Joined: Jan 2017 From: Britain Posts: 18 Thanks: 0  Problem with logs
I'm trying to solve this problem which I thought was easy: log52log2+3/2log16 which I thought should be: log 5/2^2 + log16^2/3 so: log 1.25 x log 16^2/3 not sure how to work this out help apprciated 
July 1st, 2017, 06:26 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 18,052 Thanks: 1395 
log5  2log2 + (3/2)log16 = log5  2log2 + 6log2 = log5 + 4log2 = log80

July 1st, 2017, 06:54 AM  #3 
Newbie Joined: Jan 2017 From: Britain Posts: 18 Thanks: 0  Thanks
Forgot that 3/2log16 could become 6log2, so it equals 3/2log 2^4 and you then multiply the exponent in front by 4. Have I explained that correctly? Thanks 
July 1st, 2017, 07:15 AM  #4 
Global Moderator Joined: Dec 2006 Posts: 18,052 Thanks: 1395 
3/2log16 = 3/2log(2^4) = (3/2)*4log2 = 6log2 (An explanation in words, if needed, should clearly explain the above steps.) 

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