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November 30th, 2016, 09:48 AM   #1
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A 10 year old's math assignment has me stumped... any help?

The task: Using the digits of the year 1492 once and in the order that they appear in the year, and any of the following operations: square root, factorials, exponents, decimals, parentheses, negative numbers, addition, multiplication, subtraction, division, construct all numbers from 1 to 100.

Examples:
84 = 14 x √9 x 2
90 = (1+4) x 9 x 2
My daughter has solved them all except for 53. Any help is appreciated.
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November 30th, 2016, 03:24 PM   #2
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53 = -1 + (4! + √9)*2
Thanks from topsquark and deesuwalka
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December 1st, 2016, 07:39 AM   #3
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Quote:
Originally Posted by skipjack View Post
53 = -1 + (4! + √9)*2
Thank you!!
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December 8th, 2016, 11:47 PM   #4
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Also,
53 = 1 * (sqrt(4) - 9)^2 + 2^2
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December 9th, 2016, 05:21 AM   #5
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Quote:
Originally Posted by Matthewmatician View Post
Also,
53 = 1 * (sqrt(4) - 9)^2 + 2^2
Too many dueces ... you can only use the "2" once.
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December 13th, 2016, 04:22 AM   #6
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Seeing that you came up with an equation involving "84" and including squares roots and multiplication, you can keep going higher until you find a number whose equation comes close to 1492.
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December 13th, 2016, 05:02 AM   #7
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Originally Posted by toddhicks209 View Post
Seeing that you came up with an equation involving "84" and including squares roots and multiplication, you can keep going higher until you find a number whose equation comes close to 1492.
I don't think you understand the original problem ...

Using the digits 1, 4, 9, and 2 only once in that order, form expressions that equal every number from 1 to 100, not 1492
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