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October 19th, 2016, 10:29 AM   #1
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Express 14-8√60÷6√20-10√12 in the form a√b+6√3; where a & b are irrational numbers.
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November 4th, 2016, 04:54 AM   #2
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This question looks a bit strange. Where did it come from?
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November 4th, 2016, 10:14 AM   #3
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Quote:
Originally Posted by Hezekiah View Post
Express 14-8√60÷6√20-10√12 in the form a√b+6√3; where a & b are irrational numbers.
The obvious way to attack this problem, which looks VERY strange as skipjack said, is to set up an equation. What exactly IS the problem anyway? Please be exact.

$a\sqrt{b} + 6\sqrt{3} = \dfrac{14 - 8\sqrt{60}}{6\sqrt{20} - 10\sqrt{12}}\ or$

$a\sqrt{b} + 6\sqrt{3} = 14 - \dfrac{8\sqrt{60}}{6\sqrt{20}} - 10\sqrt{12}?$
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November 4th, 2016, 10:31 AM   #4
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Quote:
Originally Posted by Hezekiah View Post
Express 14-8√60÷6√20-10√12 in the form a√b+6√3; where a & b are irrational numbers.
duplicate post ... asked, answered, and thanked by the OP

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November 4th, 2016, 01:36 PM   #5
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The same question was indeed posted, and an answer was given that assumed missing parentheses as per JeffM1's first expression. Although the desired form of a√b+6√3 wasn't achieved, Hezekiah seemed pleased with the answer given, so we never found out the fully correct version of the question.
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November 4th, 2016, 01:51 PM   #6
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Quote:
Originally Posted by skipjack View Post
The same question was indeed posted, and an answer was given that assumed missing parentheses as per JeffM1's first expression. Although the desired form of a√b+6√3 wasn't achieved, Hezekiah seemed pleased with the answer given, so we never found out the fully correct version of the question.
It was also posted (with full solution) at MHF.

-Dan
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