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 October 8th, 2016, 09:31 PM #1 Newbie   Joined: Oct 2016 From: Singapore Posts: 4 Thanks: 0 Function Question A function f is defined by f(x) = 3 -2x, for all real values of x, -1
October 8th, 2016, 09:49 PM   #2
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Quote:
 Originally Posted by Mathtan A function f is defined by f(x) = 3 -2x, for all real values of x, -1
$f(x) = \dfrac x 2$

$3 - 2x = \dfrac x 2$

$6 - 4x = x$

$6 = 5x$

$x = \dfrac 6 5$

 October 9th, 2016, 01:20 AM #3 Newbie   Joined: Oct 2016 From: Singapore Posts: 4 Thanks: 0 What is the meaning of halved under f?
 October 9th, 2016, 01:21 AM #4 Newbie   Joined: Oct 2016 From: Singapore Posts: 4 Thanks: 0 Thanks for your reply @romsek
 October 9th, 2016, 02:47 AM #5 Global Moderator   Joined: Dec 2006 Posts: 16,919 Thanks: 1253 Your formal answer should also point out that x = 6/5 satisfies -1 < x $\small\leqslant$ 5.

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