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November 9th, 2016, 05:19 AM   #31
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Amen.
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November 11th, 2016, 03:49 PM   #32
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November 12th, 2016, 01:07 AM   #33
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As x and y are the zeros of u² - 4u + 5, 1/x and 1/y are the zeros of 5v² - 4v + 1, and so their sum is 4/5.
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November 15th, 2016, 11:00 PM   #34
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Although this problem is impossible to solve, you can make things easier in the future by making it so that the solution of x+y is larger than that for x times y.
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November 16th, 2016, 03:58 AM   #35
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That doesn't make sense.
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November 16th, 2016, 05:12 AM   #36
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Beer soaked ramblings follow.
Quote:
Originally Posted by toddhicks209 View Post
Although this problem is impossible to solve, you can make things easier in the future by making it so that the solution of x+y is larger than that for x times y.
Say what?
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December 1st, 2016, 01:43 AM   #37
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$x+y=4...........(1)$

$xy=5.............(2)$

dividing eq(1) by $xy$

$\dfrac{x}{xy}+\dfrac{y}{xy}=\dfrac{4}{xy}$

$\dfrac{1}{y}+\dfrac{1}{x}=\dfrac{4}{xy}$

since $xy=5$

therefore,

$\dfrac{1}{y}+\dfrac{1}{x}=\dfrac{4}{5}$
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