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 September 14th, 2016, 04:34 AM #1 Member   Joined: Aug 2011 Posts: 78 Thanks: 0 Simple Maths Problem Hi, I am trying to phrase this maths problem easier and have a better understanding of the calculation. It is a rather simple problem which I cannot find an easier solution to. 20 cars pass a house within 10 minutes. Work out how many cars pass the house in a minute. 20/10 = 2 cars per minute So every 30 seconds a car goes past the house. How can I show this as a calculation? Can I go 1 (1 car) /2 (2 cars) * 60 = 30s? Or is there a better way?? If I go 20/600 seconds = 0.03 which is the wrong answer.
 September 14th, 2016, 04:45 AM #2 Senior Member   Joined: Aug 2016 From: morocco Posts: 273 Thanks: 32 convert minutes to seconds.
September 14th, 2016, 04:48 AM   #3
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Quote:
 Originally Posted by abdallahhammam convert minutes to seconds.
Hi thanks for the reply if I do this I end up with 0.03.

If I go 10/20 * 60 this is 30 seconds but why do I go time/cars not cars/time for the answer?

 September 14th, 2016, 04:54 AM #4 Senior Member   Joined: Aug 2016 From: morocco Posts: 273 Thanks: 32 20 cars within 10 mn means 20 cars within 600 s 1 car within 600/20=30 s. Thanks from dthomas86
September 14th, 2016, 05:36 AM   #5
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Quote:
 Originally Posted by abdallahhammam 20 cars within 10 mn means 20 cars within 600 s 1 car within 600/20=30 s.
Hi this makes sense. I over complicated it by working out the cars per minute first. Could I do it this way?

 September 14th, 2016, 05:45 AM #6 Senior Member   Joined: Aug 2016 From: morocco Posts: 273 Thanks: 32 1 car within 30s =1/30= 0.03333333 car per second but 0.033333 car has no sens. Thanks from dthomas86
 September 14th, 2016, 07:11 AM #7 Senior Member   Joined: Apr 2014 From: UK Posts: 765 Thanks: 288 I like the original reduction to 2 cars per minute to start with. What's the actual question? I assume it is along the lines of: "What is the average time between the cars passing the house" So, convert 2 cars per minute to: 2 cars per 60 seconds (2/60) reduce to: 1 car per 30 seconds (1/30) since 1 car per 30 seconds is a frequency, we can convert that to a time period because we know that T = 1/f (Time period is 1/frequency) so, 1/(1/30) = 30 Thanks from dthomas86
 September 14th, 2016, 10:02 AM #8 Member   Joined: Aug 2011 Posts: 78 Thanks: 0 Thanks for the help everyone. Really appreciate it. I just got confused in my head about the way to tackle it. Like anything in maths there are numerous ways to tackle a question.
 September 14th, 2016, 11:43 AM #9 Member   Joined: Aug 2011 Posts: 78 Thanks: 0 Sorry here's an other one in regards to a voucher scheme: 500 voucher points = £5 Every £1 spent = 5 voucher points. Now for the math involved. I've worked out one voucher =£0.01 As Pound per voucher = £5/500 voucher points What's the math involved for £1 spent = voucher points? 500 vouchers/£5 = £100 Voucher per pound 500 vouchers/£100 = 5 vouchers OR 500 vouchers/£5 = £100? So £100/£100 = £1 Is there an other way that is easier lol. Sorry I don't understand how to put it into context. I hate word problems much rather algebra for some reason. I guess I can easily convert this into algebra? Last edited by dthomas86; September 14th, 2016 at 12:29 PM.
September 25th, 2016, 08:49 AM   #10
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Quote:
 Originally Posted by abdallahhammam 20 cars within 10 mn means 20 cars within 600 s 1 car within 600/20=30 s.

This would give you the seconds per car yes? I've always found division confusion between which number you want as a numerator and denominator when faced with a word puzzle. Is it always what you are trying to find is the numerator?

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### p and q arepoints with coordinates 2,-1 and -3,4. find coordinates if point r such that pr is 2/5 of pq solve this maths priblem

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