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January 22nd, 2013, 02:42 AM   #1
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Math Possibilities

Hello everyone. MY first time here Hope someone can help me this problem.

Peter has fewer than 1000 cars. With that in the large parking lot he made 5 equal rows of cars and have one car left. He also made 4 equal rows of cars and also have one car left. He then made 9 equal rows of cars and didnt have any cars left. He can have six possibilities. So how many cars does he have?

Thank you all , Marta
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January 22nd, 2013, 07:11 AM   #2
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Re: Math Possibilities

81 or 261 or 441 or 621 or 801 or 981
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January 22nd, 2013, 09:34 AM   #3
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Re: Math Possibilities

Denis thank you so much. But would you pls explain how you arrive to those numbers. Was there a formula used, short cut or how?
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January 22nd, 2013, 02:49 PM   #4
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Re: Math Possibilities

Hello, Marta!

Welcome aboard!


Quote:
Peter has fewer than 1000 cars.
In the large parking lot he made 5 equal rows of cars and had one car left.
He also made 4 equal rows of cars and also had one car left.
He then made 9 equal rows of cars and didn't have any cars left.
How many cars does he have?






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January 23rd, 2013, 08:02 AM   #5
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Re: Math Possibilities

N = 5a + 1
N = 4b + 1

0 = 5a - 4b, a/b = 4/5 so b is a multiple of 5.

Starting at 20, add 45 (smallest multiple of 5 divisible by 9):

b, 4b + 1

20, 81
65, 261
110, 441
155, 621
200, 801
245, 981.
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