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 May 19th, 2016, 07:16 AM #1 Banned Camp   Joined: May 2016 From: earth Posts: 703 Thanks: 56 Laplace transform What is laplace transform?
May 19th, 2016, 08:54 AM   #2
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Quote:
 Originally Posted by MMath What is laplace transform?
Let me google that for you

 May 23rd, 2016, 03:38 AM #3 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 Seriously? You are asking about "Laplace Transforms", a topic from post-Calculus "differential equations" and you just recently were asking about Roman Numerals, exponentials, and logarithms! Where are you getting all these? Thanks from MMath
 May 23rd, 2016, 03:40 AM #4 Senior Member   Joined: Feb 2016 From: Australia Posts: 1,838 Thanks: 653 Math Focus: Yet to find out. He has a degree in electrical engineering so i'm told. Just refreshing his memory. Thanks from MMath
May 23rd, 2016, 04:56 AM   #5
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Quote:
 Originally Posted by Country Boy Seriously? You are asking about "Laplace Transforms", a topic from post-Calculus "differential equations" and you just recently were asking about Roman Numerals, exponentials, and logarithms! Where are you getting all these?
And he asked the question about Laplace transforms in the Elementary Math forum, too

May 23rd, 2016, 05:51 AM   #6
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 Originally Posted by Joppy He has a degree in electrical engineering so i'm told. Just refreshing his memory.
... from a past life?

 May 23rd, 2016, 06:00 AM #7 Banned Camp   Joined: May 2016 From: earth Posts: 703 Thanks: 56 hello, The huge syllabus has place less memory. so, i am trying to implement practically again.
 May 29th, 2016, 04:23 AM #8 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 The Laplace transform is the operator that "transforms" the function f(x) to the function $\displaystyle L(f(x))= \int_0^\infty f(t)e^{-st}dt$, a function of "s". It has the property that $\displaystyle L(f'(x))= \int_0^\infty e^{-st} f'(t)dt= \left[e^{-st}f(t)\right]_0^\infty+ \frac{1}{s}\int_0^\infty e^{-st}f(t)dt= f(0)+ \frac{1}{s}L(f(t))$ (assuming f goes to 0 as x goes to infinity). That is, the Laplace transform of the derivative of f can be expressed in terms of the Laplace transform of f. That allows us to change differential equation in f (equations involving the derivatives of f) to an algebraic equation in the Laplace transform of f.

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