
Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion 
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March 31st, 2016, 12:57 AM  #1 
Senior Member Joined: Feb 2014 Posts: 112 Thanks: 1  Logarithm feature
Hello, Is this true? with which formula? Thanks 
March 31st, 2016, 02:48 AM  #2 
Senior Member Joined: Dec 2012 From: Hong Kong Posts: 853 Thanks: 311 Math Focus: Stochastic processes, statistical inference, data mining, computational linguistics 
$\displaystyle \log{1} + \log{2} + \log{3} + \log{4} + ... + \log{n} = \log{(1 \cdot 2 \cdot 3 \cdot 4 \cdot ... \cdot n)} =\log{(n \cdot (n1) \cdot (n2) \cdot (n3) \cdot ... \cdot 1)} = \log{n!}$

March 31st, 2016, 05:21 AM  #3 
Math Team Joined: Jan 2015 From: Alabama Posts: 2,822 Thanks: 750 
The "formula used" is log(a)+ log(b)= log(ab), extended to n terms.


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