My Math Forum Logarithm feature

 Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion

March 30th, 2016, 11:57 PM   #1
Senior Member

Joined: Feb 2014

Posts: 114
Thanks: 1

Logarithm feature

Hello,
Is this true? with which formula? Thanks
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 March 31st, 2016, 01:48 AM #2 Senior Member   Joined: Dec 2012 From: Hong Kong Posts: 853 Thanks: 311 Math Focus: Stochastic processes, statistical inference, data mining, computational linguistics $\displaystyle \log{1} + \log{2} + \log{3} + \log{4} + ... + \log{n} = \log{(1 \cdot 2 \cdot 3 \cdot 4 \cdot ... \cdot n)} =\log{(n \cdot (n-1) \cdot (n-2) \cdot (n-3) \cdot ... \cdot 1)} = \log{n!}$ Thanks from life24 and Country Boy
 March 31st, 2016, 04:21 AM #3 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,199 Thanks: 872 The "formula used" is log(a)+ log(b)= log(ab), extended to n terms. Thanks from 123qwerty and life24

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