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 February 24th, 2016, 12:27 AM #1 Member   Joined: Jan 2016 From: Uk Posts: 80 Thanks: 2 Converting Degrees minutes to decimal Hi, When converting from Degree minutes etc to decimal and visa versa, I need to borrow but don't know how to do it. (I've realised that I don't know how to ask the question so here's an example) 50.5Deg so (.5) /.6 +the 50= 50.8 (Now the other way) 50.8 .8x.6 + the 50= 50.6 Now if I used a larger number after the '.' 50.7Deg (.7)/.6 = 1.1666 +the 50 = 51.1666 What I want is get the 1 from the 51 so that 1.1666x.6 = 0.7 then + 50 = 50.7 Camerart. Last edited by camerart; February 24th, 2016 at 01:07 AM.
 February 24th, 2016, 03:19 AM #2 Math Team   Joined: Jul 2011 From: Texas Posts: 2,761 Thanks: 1416 Converting decimal degrees to degrees and minutes ... $50.5^\circ = 50^\circ + 0.5(60') = 50^\circ \, 30'$ $50.7^\circ = 50^\circ + 0.7(60') = 50^\circ \, 42'$ ... note $0.1^\circ = 6'$ Converting degrees and minutes to a decimal ... $49^\circ \, 48' = 48^\circ + \left(\dfrac{48}{60}\right)^\circ = 48.8^\circ$ Check out the video for a more complete explanation ... Thanks from Country Boy and Joppy
 March 11th, 2016, 12:19 AM #3 Newbie   Joined: Mar 2016 From: Philippines Posts: 1 Thanks: 0 The calculation equation is simply: Decimal degrees = whole number of degrees, plus minutes divided by 60, plus seconds divided by 3600
March 18th, 2016, 02:56 AM   #4
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Quote:
 Originally Posted by skeeter Converting decimal degrees to degrees and minutes ... $50.5^\circ = 50^\circ + 0.5(60') = 50^\circ \, 30'$ $50.7^\circ = 50^\circ + 0.7(60') = 50^\circ \, 42'$ ... note $0.1^\circ = 6'$ Converting degrees and minutes to a decimal ... $49^\circ \, 48' = 48^\circ + \left(\dfrac{48}{60}\right)^\circ = 48.8^\circ$ Check out the video for a more complete explanation ...
Hi S,

C.

March 21st, 2016, 11:59 AM   #5
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Quote:
 Originally Posted by camerart Hi, When converting from Degree minutes etc to decimal and visa versa, I need to borrow but don't know how to do it. (I've realised that I don't know how to ask the question so here's an example) 50.5Deg so (.5) /.6 +the 50= 50.8 (Now the other way) 50.8 .8x.6 + the 50= 50.6
The way you have written this is very confusing! Apparently you are using "50.5Deg" to mean "50 degrees and 5 minutes". There are 60 minutes in a degree. 5 minutes is 5/60= 1/12= .08333... of a degree. 50 degrees and 5 minutes is 50.08333.. degrees not 50.8 degrees even after rounding.

Quote:
 Now if I used a larger number after the '.' 50.7Deg (.7)/.6 = 1.1666 +the 50 = 51.1666 What I want is get the 1 from the 51 so that 1.1666x.6 = 0.7 then + 50 = 50.7 Camerart.
Again, does "50.7 Deg" mean 50 degrees and 7 minutes or 50 and 7/10 degree? If it is 50 degrees and 7 minutes, then since there are 60 minutes in a degree, 7 minutes is 7/60= 0.11666... so 50 degrees and 7 minutes is 50.11666... degrees. If you mean 50 and 7/10 degrees then .7(60)= 42 degrees and 60 and 7/10 degrees is 50 degrees and 42 minutes.

 March 22nd, 2016, 02:12 AM #6 Member   Joined: Jan 2016 From: Uk Posts: 80 Thanks: 2 Hi, I still get mixed up between: Degrees, Mins decimal mins and Degrees, mins and seconds and Degrees and decimal mins seconds. Here is an NMEA sentence: \$GPGGA,FIELD.00,1234.50000,N,xxxxx.xxxx,W,1,08,0.9 ,000.0,M,46.9,M,,*47 The digits before the N are Latitude, and = 12Deg 34Mins .50000 So Degrees, Mins and decimal mins. This would convert to Degrees, Mins and seconds, So 12Deg, 34Mins and 30 seconds. And for even more complication Degrees, and decimal Mins, seconds. I sometimes need to convert between all three of these, but I can appreciate that converting to NMEA sentences is a lot of work, so keep it simple for your own amusement C.

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