
Elementary Math Fractions, Percentages, Word Problems, Equations, Inequations, Factorization, Expansion 
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November 1st, 2015, 10:44 AM  #1 
Newbie Joined: Oct 2015 From: Korce Posts: 6 Thanks: 0  math problem
one city's population is 75000. every year it increases with 2/100. how many people will there be after 1 year? answer is 76500 but i need the steps. 
November 1st, 2015, 11:08 AM  #2 
Math Team Joined: Jul 2011 From: Texas Posts: 2,692 Thanks: 1351 
2/100 = 0.02, a 2% increase ... 1.02(75000) = 76500 
November 1st, 2015, 11:11 AM  #3 
Newbie Joined: Oct 2015 From: Korce Posts: 6 Thanks: 0 
thanks!

November 1st, 2015, 11:12 AM  #4 
Newbie Joined: Oct 2015 From: Korce Posts: 6 Thanks: 0 
but i don't understand where did you get the 1.02 from

November 1st, 2015, 11:27 AM  #5 
Math Team Joined: Jan 2015 From: Alabama Posts: 2,922 Thanks: 785 
The original amount was 75000. The increase was 2% or 0.02 times 75000. You could do that either as 75000+ 0.02(75000)= 75000+ 1500 or as 75000+ 0.02(75000)= 75000(1+ 0.02)= 75000(1.02).


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