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 November 1st, 2015, 09:44 AM #1 Newbie   Joined: Oct 2015 From: Korce Posts: 6 Thanks: 0 math problem one city's population is 75000. every year it increases with 2/100. how many people will there be after 1 year? answer is 76500 but i need the steps.
 November 1st, 2015, 10:08 AM #2 Math Team   Joined: Jul 2011 From: Texas Posts: 2,771 Thanks: 1426 2/100 = 0.02, a 2% increase ... 1.02(75000) = 76500 Thanks from ariorakip
 November 1st, 2015, 10:11 AM #3 Newbie   Joined: Oct 2015 From: Korce Posts: 6 Thanks: 0 thanks!
 November 1st, 2015, 10:12 AM #4 Newbie   Joined: Oct 2015 From: Korce Posts: 6 Thanks: 0 but i don't understand where did you get the 1.02 from
 November 1st, 2015, 10:27 AM #5 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,261 Thanks: 894 The original amount was 75000. The increase was 2% or 0.02 times 75000. You could do that either as 75000+ 0.02(75000)= 75000+ 1500 or as 75000+ 0.02(75000)= 75000(1+ 0.02)= 75000(1.02). Thanks from ariorakip

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