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 October 24th, 2007, 11:18 AM #11 Senior Member   Joined: May 2007 Posts: 402 Thanks: 0 Hm.. Well, with t=10, the height comes up to 40m! So, I don't thing that's right! And another thing: haven't we gone back to the "wrong" equation? When t=0, h!=90..
 October 24th, 2007, 02:43 PM #12 Newbie   Joined: Oct 2007 Posts: 8 Thanks: 0 Geez, and I thought I had it right. I'm a little more confused now...
October 25th, 2007, 04:30 PM   #13
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Quote:
 Originally Posted by milin Hm.. Well, with t=10, the height comes up to 40m! So, I don't thing that's right! And another thing: haven't we gone back to the "wrong" equation? When t=0, h!=90..
The equation you suggested made more sense, but Jemelly decided to stick with h=-4.9t^2+42t+110, which gives h=110 when the ball is thrown from the 90 m cliff. Hence it's only logical for h(10) to be 40 when the ball is only 20 m above ground level.

 October 25th, 2007, 07:43 PM #14 Newbie   Joined: Oct 2007 Posts: 8 Thanks: 0 I had to stick to h=-4.9t^2+42t+110 because that is what was printed on my handout from my teacher. Anyway, I turned it in today for better or worse. Thanks for all your help!

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### c=0.013x^2-1.19x 28.24

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