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July 30th, 2014, 07:02 AM   #1
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loge-1

I have an equation with a loge to the power of minus 1. How do I calculate the answer?

LogeToThePowerOfMinus1(-0.1488x30)

The answer is 0.0117
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July 30th, 2014, 07:58 PM   #2
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$$\log{ \mathbb{e}^{-1} } = -1 \log \mathbb{e} = -1 \cdot 1 = -1$$
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July 30th, 2014, 08:09 PM   #3
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Please ask someone to show you how to post properly.

Also, there is no equation shown: an equation has an equal sign.

If there is a multiplication involved, use * (not x) as multiplication sign.
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