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 July 30th, 2014, 07:02 AM #1 Newbie   Joined: Jul 2014 From: UK Posts: 1 Thanks: 0 loge-1 I have an equation with a loge to the power of minus 1. How do I calculate the answer? LogeToThePowerOfMinus1(-0.1488x30) The answer is 0.0117
 July 30th, 2014, 07:58 PM #2 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,655 Thanks: 2633 Math Focus: Mainly analysis and algebra $$\log{ \mathbb{e}^{-1} } = -1 \log \mathbb{e} = -1 \cdot 1 = -1$$
 July 30th, 2014, 08:09 PM #3 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,413 Thanks: 1024 Please ask someone to show you how to post properly. Also, there is no equation shown: an equation has an equal sign. If there is a multiplication involved, use * (not x) as multiplication sign.

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# loge^-1(- 0.1488*30)

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