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December 13th, 2013, 06:30 AM  #1 
Newbie Joined: Oct 2013 Posts: 25 Thanks: 0  Reaction Functions
How do I get from the following reaction function to the unique Nash equilibrium? Reaction function: p(i)(p(j))= 6 + 0.25(phi*p(j) Nash equilibrium: p(i)=p(j)= 24/(4 phi) 
December 15th, 2013, 02:17 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,942 Thanks: 2210 
The parentheses don't balance. Was this set as a problem?

December 16th, 2013, 05:43 AM  #3 
Newbie Joined: Oct 2013 Posts: 25 Thanks: 0  Re: Reaction Functions
Let me try to make it more clear. I've got two reaction functions. I presume I have to substitute in order to get the, but somehow I don't get it. So the reaction function is: pi(pj)= 6 + 'weird symbol'*pj/4 And the solution of the reaction functions should be: pi=pj=24/(4 'weird symbol') 

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