
Economics Economics Forum  Financial Mathematics, Econometrics, Operations Research, Mathematical Finance, Computational Finance 
 LinkBack  Thread Tools  Display Modes 
December 14th, 2011, 10:53 AM  #1 
Joined: Dec 2011 Posts: 9 Thanks: 0  question
You are approaching your 10year anniversary of employment, and the company your work for has promised a bonus of $10,000 in two years time if you reach performance targets. In addition, the company has promised you another bonus of $30,000 seven years from today if your high standards of work performance continue. Interest rates are currently 5% and will stay at this level for four years. After four years, interest rates are expected to rise to 8%. What is the present value of the promised bonuses? Do I add all the values together or do I simply calculate FV= 10,000 i= 5% n=2 
December 14th, 2011, 02:16 PM  #2 
Global Moderator Joined: Nov 2006 From: UTC 5 Posts: 15,540 Thanks: 789 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms  Re: question
Compute the two future values separately and add them together.

December 14th, 2011, 09:17 PM  #3 
Joined: Apr 2011 From: USA Posts: 782 Thanks: 1  Re: question
For the $10,000 you can just take it as is, using the 5% and 2 periods. The rate doesn't change during this time. For the $30,000, you need to first find the present value of where it will be in 4 years when the rate changes. That is, you have to "back into" stuff like this. We know it's worth $30,000 in 7 years (FV). 4 years from now is a present value relative to the 7 years. So how many years will it be at 8%? First find the present value it will be at the 4year mark, at 8%. Then take that value and find the present value of it for the first 4 years at the 5%. Does that make sense? You can't add the original numbers together as they are two individual things. Whether you'd want to add the answers together I don't know. The wording isn't clear on that point. Unless you're using a template that only has space for one number, I would list them individually. 
December 16th, 2011, 12:55 AM  #4 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 4,217 Thanks: 243  Re: question
30000 / (1.05^4 * 1.08^3) = ~19,592.63
