
Differential Equations Ordinary and Partial Differential Equations Math Forum 
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May 28th, 2007, 10:15 AM  #1 
Newbie Joined: May 2007 Posts: 1 Thanks: 0  Differential equation
Hi, I need a little help on this problem. I am asked to find the equilibrium solution to this DE: y' = e^(t) + y If I set y' to zero, I get 0 = e^(t) + y then... y = e^(t) lny = t Is this correct? 
May 29th, 2007, 01:54 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,484 Thanks: 2041 
The equation you gave has solution y = c e^t  ½ e^(t). There is no equilibrium solution in the usual sense of equilibrium. Can you explain what was meant by "equilibrium solution" in this question? 
May 29th, 2007, 06:26 PM  #3 
Newbie Joined: May 2007 Posts: 2 Thanks: 0 
Well, I need to draw a slope field for this differential equation and assumedd that it will have an equilibrium solution that either diverges or converges.


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