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 Differential Equations Ordinary and Partial Differential Equations Math Forum

 May 28th, 2007, 10:15 AM #1 Newbie   Joined: May 2007 Posts: 1 Thanks: 0 Differential equation Hi, I need a little help on this problem. I am asked to find the equilibrium solution to this DE: y' = e^(-t) + y If I set y' to zero, I get 0 = e^(-t) + y then... -y = e^(-t) ln|-y| = -t Is this correct? May 29th, 2007, 01:54 AM #2 Global Moderator   Joined: Dec 2006 Posts: 20,919 Thanks: 2202 The equation you gave has solution y = c e^t - ½ e^(-t). There is no equilibrium solution in the usual sense of equilibrium. Can you explain what was meant by "equilibrium solution" in this question? May 29th, 2007, 06:26 PM #3 Newbie   Joined: May 2007 Posts: 2 Thanks: 0 Well, I need to draw a slope field for this differential equation and assumedd that it will have an equilibrium solution that either diverges or converges. Tags differential, equation Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post PhizKid Differential Equations 0 February 24th, 2013 10:30 AM cheyb93 Differential Equations 3 February 7th, 2013 09:28 PM mathkid Differential Equations 0 October 9th, 2012 08:01 AM tomislav91 Differential Equations 1 May 30th, 2012 07:28 AM tsl182forever8 Differential Equations 2 March 14th, 2012 03:12 PM

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