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 June 11th, 2015, 10:20 AM #1 Newbie   Joined: Jun 2015 From: House Posts: 11 Thanks: 0 Find solutions, that agrees with given conditions For example I have this dif. equation: 4y''+4y'+y=0 I need to find a solution, with given conditions: y(0) = 2 y'(0) = 0 So I solve that equation, get: k1 = k2 = -0,5 So y = (C1+C2x)e^(-0,5x) Now, to agree to those conditions, what I do: y(0) = 2. I change x to 0 in y and get C1 = 2 Then I find derivative of y, do the same thing y'(0) = 0 Then I found C2. I put values of C1,C2 in y and that's the answer? June 11th, 2015, 12:46 PM #2 Senior Member   Joined: Mar 2011 From: Chicago, IL Posts: 214 Thanks: 77 If I have not made a mistake , I found that $\displaystyle C_2=1$. So, you are right - just to substitute $\displaystyle C_1$ and $\displaystyle C_2$ with 2 and 1 respectively: $\displaystyle y=(2+x)e^{-0.5x}$ Tags agrees, conditions, find, solutions Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Albert.Teng Algebra 6 December 28th, 2013 06:44 AM n777l Algebra 2 September 20th, 2013 04:56 PM chris99191 Algebra 10 April 22nd, 2011 02:10 AM 450081592 Calculus 1 October 3rd, 2010 10:21 PM 450081592 Linear Algebra 3 November 29th, 2009 10:20 AM

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