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Differential Equations Ordinary and Partial Differential Equations Math Forum


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May 13th, 2015, 10:36 AM   #11
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i just don't see how did you get from

y′y′′′−3y′′2−2y′5y3=y′2(y′y ′′−(y′′)2y′2−2(y′′2y′2+y′3 y3))=y′2(ddxy′′y′−2(y′′2y′2+y′3y 3))=0

to
y′′y′−2logy′′2y′y3=c

where and how to do the integration
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May 13th, 2015, 11:17 AM   #12
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Actually, that integration is not valid.
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May 13th, 2015, 12:21 PM   #13
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because of the ln part, right? it's not the differential.. isn't it?
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May 13th, 2015, 12:28 PM   #14
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Yes, I forgot about the exponents when I was thinking about it.
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