May 13th, 2015, 10:36 AM  #11 
Newbie Joined: May 2015 From: Israel Posts: 6 Thanks: 0 
i just don't see how did you get from yâ€²yâ€²â€²â€²âˆ’3yâ€²â€²2âˆ’2yâ€²5y3=yâ€²2(yâ€²yâ €²â€²â€²âˆ’(yâ€²â€²)2yâ€²2âˆ’2(yâ€²â€²2yâ€²2+yâ€²3 y3))=yâ€²2(ddxyâ€²â€²yâ€²âˆ’2(yâ€²â€²2yâ€²2+yâ€²3y 3))=0 to yâ€²â€²yâ€²âˆ’2logyâ€²â€²2yâ€²y3=c where and how to do the integration thank you 
May 13th, 2015, 11:17 AM  #12 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,671 Thanks: 2651 Math Focus: Mainly analysis and algebra 
Actually, that integration is not valid.

May 13th, 2015, 12:21 PM  #13 
Newbie Joined: May 2015 From: Israel Posts: 6 Thanks: 0 
because of the ln part, right? it's not the differential.. isn't it?

May 13th, 2015, 12:28 PM  #14 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,671 Thanks: 2651 Math Focus: Mainly analysis and algebra 
Yes, I forgot about the exponents when I was thinking about it.


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