My Math Forum Using Separation of variables

 Differential Equations Ordinary and Partial Differential Equations Math Forum

May 2nd, 2015, 06:57 PM   #1
Newbie

Joined: Sep 2014
From: n/a

Posts: 9
Thanks: 0

Using Separation of variables

Hello everyone,

I am having an issue with this concept. I am running into having a second order differential equation when I am using the separation of variables method. I would normally type the problem into this text space but I figured it was better for me to upload a picture created from microsoft's word processor with the formatting of equations.

Please see attached jpeg for problem.

So since I have a second order and there are three different ways for me to solve a second order, would the general solution of the second order include a summation to cover for all three cases?
Attached Images
 seperation of variables.jpg (32.5 KB, 16 views)

Last edited by philm; May 2nd, 2015 at 07:00 PM. Reason: Forgot to upload document

 May 2nd, 2015, 09:51 PM #2 Senior Member   Joined: Aug 2014 From: United States Posts: 137 Thanks: 21 Math Focus: Learning Yes, I believe that the general solution is the sum of all distinct solutions. Assuming all different methods give you different solutions, your answer would be a sum of all those solutions.
 May 3rd, 2015, 04:48 PM #3 Newbie   Joined: Sep 2014 From: n/a Posts: 9 Thanks: 0 Hm, intersting, There are three different cases depending on the complex roots of the 2nd order characteristic equation. This is all good and everything but the lambda is causing a huge issue since it is unknown. After working out the complex roots, I determined the three cases (w = lambda) 1) w = 1/4 2) w > 1/4 3) w < 1/4 I am not too sure but I think that there is a particular case that I have to choose from for this specific problem? Or do I have to solve the PDE for all three cases?
 May 5th, 2015, 04:38 PM #4 Newbie   Joined: Sep 2014 From: n/a Posts: 9 Thanks: 0 I was able to solve this problem
May 6th, 2015, 06:37 AM   #5
Senior Member

Joined: Aug 2014
From: United States

Posts: 137
Thanks: 21

Math Focus: Learning
Quote:
 Originally Posted by philm I was able to solve this problem
Great! Did you need to solve all three cases?

 May 6th, 2015, 11:41 AM #6 Newbie   Joined: Sep 2014 From: n/a Posts: 9 Thanks: 0 I had to take the summation of the separation of variables. Then, u(x, t) only existed at one value, n = 1. At that point, lambda went away. It was a little tricky this one. Then I solved the 2nd order ODE using IC and BC.

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post Sefrez Applied Math 1 October 26th, 2013 10:21 AM John Creighton Economics 0 March 16th, 2012 09:46 PM engininja Calculus 2 February 22nd, 2011 02:06 PM engininja Calculus 4 September 23rd, 2010 12:58 AM zaserov Calculus 1 October 25th, 2007 02:11 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top