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April 16th, 2015, 03:17 AM  #1 
Member Joined: Apr 2014 From: australia Posts: 68 Thanks: 32  Ode
Hi, just want to check if i have obtained the correct answer for the question below: dy/dt = 4y (x^3  1/2); a) Find ODE solution subject to initial conditions y(1) = 3/e. b) Find y(1) Ans (a) For the general solution i get, y = Ce^(x^4  2x) At initial condition y(1) = 3/e y =3e^(x^4  2x) Ans (b) 3e thanks in advance 
April 16th, 2015, 03:33 AM  #2  
Math Team Joined: May 2013 From: The Astral plane Posts: 2,158 Thanks: 878 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
Dan Edit: Yup. It's a typo. You have the correct solution, but look at y(1) again. $\displaystyle y(1) = 3 \cdot exp((1)^4  2(1)) = 3 \cdot exp(1 + 2) = 3e^3$. Dan Last edited by topsquark; April 16th, 2015 at 03:38 AM.  
April 16th, 2015, 03:52 AM  #3 
Member Joined: Apr 2014 From: australia Posts: 68 Thanks: 32 
thanks, yes it was a typo as you noticed. thanks again.
