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OdeHi, just want to check if i have obtained the correct answer for the question below: dy/dt = 4y (x^3 - 1/2); a) Find ODE solution subject to initial conditions y(1) = 3/e. b) Find y(-1) Ans (a) For the general solution i get, y = Ce^(x^4 - 2x) At initial condition y(1) = 3/e y =3e^(x^4 - 2x) Ans (b) 3e thanks in advance |

Quote:
-Dan Edit: Yup. It's a typo. You have the correct solution, but look at y(-1) again. $\displaystyle y(-1) = 3 \cdot exp((-1)^4 - 2(-1)) = 3 \cdot exp(1 + 2) = 3e^3$. -Dan |

thanks, yes it was a typo as you noticed. thanks again. |

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