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November 18th, 2014, 06:32 PM   #1
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How do I take this inverse laplace

1/(4s+1)

Answer should be:
1/4*e^(-t/4)
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November 19th, 2014, 12:33 AM   #2
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Quote:
Originally Posted by shreddinglicks View Post
1/(4s+1)

Answer should be:
1/4*e^(-t/4)
You reduce it to a form in the lookup table of Laplace transforms that you have. In this case the relevant item in the table I use is:
$${\large{\mathcal{L}}} e^{a t}=\frac{1}{s-a}$$
So you rearrange your LT to be:$$f(s)=\frac{1}{4}\left(\frac{1}{s-(-1/4)}\right)$$
...

CB
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