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 November 18th, 2014, 06:32 PM #1 Member   Joined: Oct 2014 From: NJ Posts: 44 Thanks: 2 How do I take this inverse laplace 1/(4s+1) Answer should be: 1/4*e^(-t/4)
November 19th, 2014, 12:33 AM   #2
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Joined: Jan 2012
From: Erewhon

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Quote:
 Originally Posted by shreddinglicks 1/(4s+1) Answer should be: 1/4*e^(-t/4)
You reduce it to a form in the lookup table of Laplace transforms that you have. In this case the relevant item in the table I use is:
$${\large{\mathcal{L}}} e^{a t}=\frac{1}{s-a}$$
So you rearrange your LT to be:$$f(s)=\frac{1}{4}\left(\frac{1}{s-(-1/4)}\right)$$
...

CB

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