October 23rd, 2014, 04:38 PM  #1 
Member Joined: Oct 2014 From: NJ Posts: 46 Thanks: 2  Why is the value of s = 1/3?
a mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest from a point 3 inches above the equilibrium position F = ks 24 = k*(1/3) why is it 1/3 inches and not 4 inches? 
October 23rd, 2014, 05:03 PM  #2  
Math Team Joined: May 2013 From: The Astral plane Posts: 2,226 Thanks: 908 Math Focus: Wibbly wobbly timeywimey stuff.  Quote:
Dan  
October 23rd, 2014, 05:06 PM  #3  
Member Joined: Oct 2014 From: NJ Posts: 46 Thanks: 2  Quote:
I also think that s = 4, but my teachers answer key says s = 1/3. I searched the question on Google and it also says s = 1/3.  
October 23rd, 2014, 05:28 PM  #4 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,671 Thanks: 2651 Math Focus: Mainly analysis and algebra 
The force operates in the opposite direction to the displacement, so it always has a negative sign. The force is also proportional to displacement from the equilibrium position, so I'd expect 3 at the moment. What value are you using for gravity? The force wouldn't normally be 24 if the mass is 24 because F = mg. 
October 23rd, 2014, 05:37 PM  #5  
Member Joined: Oct 2014 From: NJ Posts: 46 Thanks: 2  Quote:
Do you know where 1/3 comes from? My teachers answer key has 24 = k*(1/3) Last edited by shreddinglicks; October 23rd, 2014 at 05:41 PM.  
October 23rd, 2014, 06:00 PM  #6 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,671 Thanks: 2651 Math Focus: Mainly analysis and algebra 
I'm a bit confused, because "pounds" is a unit of mass, not of force. So when it says 24 pounds, I assume that is the mass. Also, for which point are you trying to calculate the force? Because the force varies with the displacement $s$. 
October 23rd, 2014, 06:08 PM  #7  
Member Joined: Oct 2014 From: NJ Posts: 46 Thanks: 2  Quote:
Mass is measured in slugs, or in the SI system as the kg. Pounds is NOT a unit of mass. Pounds is a measurement of weight. By definition weight is the force of gravity on an object. That's why you will weigh less on the moon. Mass is universal. If my scanner wasn't broken I would send you the proof from my engineering and physics textbooks. According to my physics and engineering books you get the spring constant, "k" by calculating the displacement created by a force on the spring. So the value of, "s" must be 4 inches. I want the value of, "k" I already know the force is 24 pounds. My only guess is that the units for K must be, "pounds per feet," instead of, "pounds per inch." Last edited by shreddinglicks; October 23rd, 2014 at 06:16 PM.  
October 23rd, 2014, 06:17 PM  #8 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,671 Thanks: 2651 Math Focus: Mainly analysis and algebra 
Isn't $k$ supposed to be the spring constant? The spring constant is the displacement per unit force on the spring. So that would be $\frac{4}{24}= \frac16$ in/lb. I apologise if I'm wrong about pounds. I've always equated pounds with kilograms (as do most converters). 
October 23rd, 2014, 06:24 PM  #9 
Math Team Joined: May 2013 From: The Astral plane Posts: 2,226 Thanks: 908 Math Focus: Wibbly wobbly timeywimey stuff. 
I am wondering about your system of units. Specifically if you are using feet for s then an extension of 4 inches would be 1/3 feet. Dan 
October 23rd, 2014, 06:25 PM  #10  
Member Joined: Oct 2014 From: NJ Posts: 46 Thanks: 2  Quote:
k = 24/4 = 6 Also, pounds can be converted to kg for the metric system, but that is not the same as mass. You have to convert to mass from weight using f = mg. f in this case being force of gravity. f = mg is the same as Newton's f = ma. a = 9.8 m/s^2 at sea level. Last edited by shreddinglicks; October 23rd, 2014 at 06:30 PM.  

Tags 
1 or 3 
Search tags for this page 
a mass weighing 24 pounds attached to the end of a spring stretches it 4 inches,a 24 pound weight, attached to the end of a spring,A mass weighing 24 pounds attached to the end of a spring streches it 4 inches,a mass weighing 24 pounds attached to the end of a spring
Click on a term to search for related topics.

Thread Tools  
Display Modes  
