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 July 16th, 2013, 06:44 AM #1 Senior Member   Joined: Sep 2012 Posts: 112 Thanks: 0 weird differential equation I have absolutely no idea how to solve the following differential equation- $[2(st)^1^/^2 - s]. dt + ds= 0$
July 16th, 2013, 08:06 AM   #2
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From: Mehsana, Gujarat, India

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Re: weird differential equation

Quote:
 Originally Posted by helloprajna $[2(st)^1^/^2 - s]. dt + ds= 0$
$[2(st)^1^/^2 - s]dt + ds= 0$
=> $2(st)^1^/^2 - s= -ds/dt$
=> $ds/dt - s= -2(st)^1^/^2$
Let $gt; ds=2udu$
Substitute s and ds from above. Now you will find yourself a linear differential equation. Try solving it yourself.

 July 16th, 2013, 11:25 PM #3 Senior Member   Joined: Sep 2012 Posts: 112 Thanks: 0 Re: weird differential equation wow, you are great! I can solve it easily now. Thanks a lot!

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