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Lalitha183 May 14th, 2018 06:58 AM

Differential Equations
 
1 Attachment(s)
I have attached the question images Q43 & Q44. These are my previous year questions, which I was unable to solve. Kindly help me.
Thank you

Micrm@ss May 14th, 2018 07:31 AM

Why don't you just plug the different solutions into the equation and see whether you get a correct result?

v8archie May 14th, 2018 10:10 AM

That's certainly the most direct approach.

I think that the first question has an error. None of them look like solutions. I suspect the second also has an error, but it does at least have a solution.

Lalitha183 May 15th, 2018 10:18 PM

Quote:

Originally Posted by Micrm@ss (Post 594340)
Why don't you just plug the different solutions into the equation and see whether you get a correct result?

Q43. I'm getting the general solution as c1e^(2+sqrt(3))x + c2e^(2-sqrt(3))x
But I'm not sure what else needs to be done to derive one of the solutions given.
Q44. I have substituted the solutions in the D.E and I'm getting option A & B as solutions. Is it correct ?

skipjack May 16th, 2018 12:07 AM

No.

Country Boy May 16th, 2018 04:03 AM

The characteristic equation for 43 is . r= 0 is a root. so that and [tex]r= -2- \sqrt{3}[tex] are the other 2 roots.

The general solution to the differential equation is . You forgot the constant solution.

For 44 if you set y= x, then y'= 1 and y''= 0 so the equation becomes x(0)- 1+ 1= 0. If y= sin(x+ c) then y'= cos(x+ c) and y''= -sin(x+ c). The equation becomes . If y= sinh(x+ c) then y'= cosh(x+ c) and y''= sinh(x+ c). The equation becomes [tex]sinh^2(x+ c)- cosh^2(x+ c)+ 1= 0.


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