My Math Forum  

Go Back   My Math Forum > College Math Forum > Differential Equations

Differential Equations Ordinary and Partial Differential Equations Math Forum


Reply
 
LinkBack Thread Tools Display Modes
February 20th, 2017, 06:49 PM   #1
Newbie
 
Joined: Feb 2017
From: College Station

Posts: 7
Thanks: 0

How can I solve this PDE?

-(∂²u/∂x² + ∂²u/∂y²) + uk² = xk²

zero boundary conditions on the boundary of the Square Domain (0,1)X(0,1).

k^2 is a constant
Aggieland is offline  
 
Reply

  My Math Forum > College Math Forum > Differential Equations

Tags
pde, solve



Thread Tools
Display Modes


Similar Threads
Thread Thread Starter Forum Replies Last Post
Please Solve this 4 EPIC Problems.... i couldn't solve it myself gen_shao Algebra 12 November 2nd, 2014 06:11 AM





Copyright © 2017 My Math Forum. All rights reserved.