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-   -   How can I solve this PDE? (http://mymathforum.com/differential-equations/339150-how-can-i-solve-pde.html)

Aggieland February 20th, 2017 06:49 PM

How can I solve this PDE?
 
-(∂²u/∂x² + ∂²u/∂y²) + uk² = xk²

zero boundary conditions on the boundary of the Square Domain (0,1)X(0,1).

k^2 is a constant


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