My Math Forum Finding laplace transform of unit step function?

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 February 20th, 2017, 12:37 AM #1 Newbie   Joined: Feb 2017 From: malaysia Posts: 1 Thanks: 0 Finding laplace transform of unit step function? The initial function is: f(t) = 0 for 02 In function notation this function would be f(t)=U(t)-U(t-2). However the actual question is for us to find f(t-1). So what would this mean? Would it mean: f(t) = -1 for 02 or something else?
 February 20th, 2017, 03:23 AM #2 Senior Member   Joined: Feb 2016 From: Australia Posts: 1,741 Thanks: 609 Math Focus: Yet to find out. If $f(t) = U(t) - U(t - 2)$, then, $f(t - 1) = U(t - 1) - U((t - 1) - 2) = U(t - 1) - U(t - 3)$. Hence, $\displaystyle f(t - 1) =$$\displaystyle \left\{ \begin{array}{rl} 1, &\mbox{1$\displaystyle \leq$t < 3} \\ 0, &\mbox{elsewhere.} \end{array} \right.$ The Laplace Transform of $f(t - 1)$ should be straight forward to compute using tables or otherwise.

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