My Math Forum Difference equations

 Differential Equations Ordinary and Partial Differential Equations Math Forum

 December 18th, 2016, 03:09 AM #1 Newbie   Joined: Oct 2015 From: London Posts: 19 Thanks: 0 Difference equations Convert to difference equations
 December 18th, 2016, 03:26 AM #2 Senior Member   Joined: Feb 2016 From: Australia Posts: 725 Thanks: 271 Math Focus: Yet to find out. Any particular method?
 December 18th, 2016, 03:52 AM #3 Newbie   Joined: Oct 2015 From: London Posts: 19 Thanks: 0
 December 18th, 2016, 03:53 AM #4 Newbie   Joined: Oct 2015 From: London Posts: 19 Thanks: 0 yÎ„->dy/dx
 December 18th, 2016, 06:28 PM #5 Senior Member   Joined: Feb 2016 From: Australia Posts: 725 Thanks: 271 Math Focus: Yet to find out. Using the Euler backward method, $\displaystyle \frac{y(k + 1) - y(k)}{x_{k + 1} - x_k} = - a y(k), k \in \mathbb{Z}$ Where $T = x_{k + 1} - x_k$ is the sampling period. $y(k + 1) = y(k)(1 - Ta)$ The first few values of $k$ gives, $y(1) = y(0)(1 - Ta) = (1 - Ta)$ $y(2) = y(1)(1 - Ta) = (1 - Ta)^2$ ${\vdots}$ $y(k + 1) = y(k)(1 - Ta)^{k + 1}$ Not sure about this last part though , maybe wait to see what the experts say . Thanks from pass92 Last edited by Joppy; December 18th, 2016 at 06:48 PM. Reason: swapped x for t from post #4

 Tags difference, equations

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post egyvaltozos Algebra 3 October 18th, 2014 10:04 PM riotsandravess Applied Math 1 March 2nd, 2011 04:14 PM blac24 Applied Math 1 December 5th, 2009 10:07 AM scarymovie Algebra 10 October 15th, 2008 06:18 PM anthdelm Applied Math 1 February 4th, 2008 10:04 AM

 Contact - Home - Forums - Top