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May 4th, 2016, 08:42 AM   #1
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ordinary diff. eq.

solve the differential equation :
dy-dx = 2xydy
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May 4th, 2016, 09:14 AM   #2
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What happens if you write $v=xy$?
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May 4th, 2016, 09:22 AM   #3
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Use $e^{\text{y}^2}\!\!$ as an integrating factor.
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May 4th, 2016, 09:56 AM   #4
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Quote:
Originally Posted by v8archie View Post
What happens if you write $v=xy$?
please can you actually solve it so that i could easily understand?
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May 4th, 2016, 03:10 PM   #5
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Solution can be approximated
there is no exact solution as i can see
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May 4th, 2016, 05:06 PM   #6
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Given $dy = 2xydy + dx$, multiplying by $e^{y^2}\!\!$ gives $e^{y^2}dy = 2xye^{y^2}dy + e^{y^2}dx = d\!\left(\!xe^{y^2}\!\right)\!$, etc.
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