My Math Forum  

Go Back   My Math Forum > College Math Forum > Differential Equations

Differential Equations Ordinary and Partial Differential Equations Math Forum


Reply
 
LinkBack Thread Tools Display Modes
February 1st, 2016, 12:30 AM   #1
Newbie
 
Joined: Feb 2016
From: Indonesia

Posts: 1
Thanks: 0

Simple harmonic motion damping Laplace transform help!

Ok guys, so I'm really confused as why in the second order homogenous equation of
mx”(t) + cx’(t) + kx(t) = 0
where m = mass, c = drag coefficient, and k = spring constant
the Laplace transform of L{x(t)} = s L{X(t)}
Why isn't it L{x(t)} = s L{X(t)} - X(0)?
Where exactly did the "- X(0)" go?
doctordino is offline  
 
February 1st, 2016, 11:45 AM   #2
Senior Member
 
Joined: Dec 2015
From: Earth

Posts: 227
Thanks: 26

$\displaystyle x(0)=0$
(x) equals 0 for time=0
idontknow is offline  
Reply

  My Math Forum > College Math Forum > Differential Equations

Tags
damping, harmonic, laplace, motion, simple, transform



Search tags for this page
Click on a term to search for related topics.
Thread Tools
Display Modes


Similar Threads
Thread Thread Starter Forum Replies Last Post
Relatioship between Laplace and Inverse Laplace Transform from tables szz Differential Equations 1 November 2nd, 2014 03:18 AM
Simple Harmonic Motion evaeva Calculus 1 May 20th, 2014 01:39 AM
Question on simple harmonic motion Chikis Physics 1 June 26th, 2013 09:21 PM
In simple harmonic motion the accleration of the body is ma r-soy Physics 2 June 5th, 2012 11:26 AM
Simple Harmonic Motion problem shalikadm Physics 1 May 28th, 2012 05:33 PM





Copyright © 2018 My Math Forum. All rights reserved.