
Differential Equations Ordinary and Partial Differential Equations Math Forum 
 LinkBack  Thread Tools  Display Modes 
February 1st, 2016, 01:30 AM  #1 
Newbie Joined: Feb 2016 From: Indonesia Posts: 1 Thanks: 0  Simple harmonic motion damping Laplace transform help!
Ok guys, so I'm really confused as why in the second order homogenous equation of mx”(t) + cx’(t) + kx(t) = 0 where m = mass, c = drag coefficient, and k = spring constant the Laplace transform of L{x(t)} = s L{X(t)} Why isn't it L{x(t)} = s L{X(t)}  X(0)? Where exactly did the " X(0)" go? 
February 1st, 2016, 12:45 PM  #2 
Senior Member Joined: Dec 2015 From: Earth Posts: 321 Thanks: 42 
$\displaystyle x(0)=0$ (x) equals 0 for time=0 

Tags 
damping, harmonic, laplace, motion, simple, transform 
Search tags for this page 
Click on a term to search for related topics.

Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Relatioship between Laplace and Inverse Laplace Transform from tables  szz  Differential Equations  1  November 2nd, 2014 04:18 AM 
Simple Harmonic Motion  evaeva  Calculus  1  May 20th, 2014 02:39 AM 
Question on simple harmonic motion  Chikis  Physics  1  June 26th, 2013 10:21 PM 
In simple harmonic motion the accleration of the body is ma  rsoy  Physics  2  June 5th, 2012 12:26 PM 
Simple Harmonic Motion problem  shalikadm  Physics  1  May 28th, 2012 06:33 PM 