My Math Forum Non-Exact Differential equation

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 September 30th, 2012, 01:58 PM #1 Newbie   Joined: Sep 2012 Posts: 14 Thanks: 0 Non-Exact Differential equation Hi, I have another problem that I can't solve: y+2*y^7=(y^3+6*x)dy/dx which gives (y+2*y^7)dx+(-y^3-6*x)dy=0 The equation is not exact, so I tried to find the integrating factor: e^((My-Nx)/(-M)) wich gives x^(-7) When I multiply both equations by x^(-7), it's still not exact. I tried many things, but I have no idea what else to try... I need to find the solution x=(something) when the initial conditions are y(0)=1 Can someone help me please?
 September 30th, 2012, 02:28 PM #2 Senior Member   Joined: Jul 2011 Posts: 118 Thanks: 0 Re: Non-Exact Differential equation Integrating factor is $y^{-7}$
 September 30th, 2012, 02:40 PM #3 Newbie   Joined: Sep 2012 Posts: 14 Thanks: 0 Re: Non-Exact Differential equation Damn of course! Thanks a lot!

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