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March 10th, 2019, 01:47 AM   #1
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Reverse digits of pi series

Reference :

https://en.wikipedia.org/wiki/Pi

Can we write a Computer program which will print Reverse Digits of Pi series?

Final output of the program will be
5,1,4,1,3

Can we start from $\omega$ till 1 for the program?

The programming language could be LOLCODE, Befunge, Whitespace, Ook!, Malbolge, etc.

Can we name this new Mathematical series as Reverse pi number series?

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March 10th, 2019, 10:23 AM   #2
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I've been waiting for a chance to use Malbolge!

Thank you!
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March 10th, 2019, 01:25 PM   #3
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Quote:
Originally Posted by Micrm@ss View Post
Reference :

https://en.wikipedia.org/wiki/Pi

Can we write a Computer program which will print Reverse Digits of Pi series?

Final output of the program will be
5,1,4,1,3

Can we start from $\omega$ till 1 for the program?

The programming language could be LOLCODE, Befunge, Whitespace, Ook!, Malbolge, etc.

Can we name this new Mathematical series as Reverse pi number series?

Thanks & Regards
No!! There is no last digit!!
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March 10th, 2019, 01:37 PM   #4
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Quote:
Originally Posted by mathman View Post
No!! There is no last digit!!
Are you sure?
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March 10th, 2019, 02:13 PM   #5
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https://en.wikipedia.org/wiki/Proof_..._is_irrational
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March 10th, 2019, 02:15 PM   #6
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First find the n-th digit of pi and reverse it but pi is irrational.

Last edited by idontknow; March 10th, 2019 at 02:21 PM.
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March 10th, 2019, 02:27 PM   #7
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Perhaps a proof using Poe's law could work here.
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March 11th, 2019, 12:42 PM   #8
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Quote:
Originally Posted by Maschke View Post
Are you sure?
Yes. A last digit implies a finite number of digits.
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March 11th, 2019, 12:58 PM   #9
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I think he is asking to show the decimal digits of pi in reverse way but in a bounded way .
This can be done with a specific software or simple algorithms .
Approximations of pi can be used too .

If not then make a statement :
Given natural number n , find the function $\displaystyle f(n)$ that gives the number in reverse.
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March 11th, 2019, 01:05 PM   #10
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Quote:
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Yes. A last digit implies a finite number of digits.
It doesn't. The ordinal $\omega+1$ is infinite and has a last element.
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