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 November 2nd, 2018, 11:55 AM #1 Member   Joined: Oct 2017 From: Rumba Posts: 39 Thanks: 0 Algorithms question help Can someone give me guidance how to do this question: http://prntscr.com/ldp4l8 November 2nd, 2018, 01:15 PM #2 Senior Member   Joined: May 2016 From: USA Posts: 1,310 Thanks: 551 This is basically just arithmetic. You calculate $\displaystyle \frac{1}{2} * (11 * 10^6)^2 \approx what?$ $\displaystyle \frac{1}{2} * (60 * 10^6)^2 \approx what?$ $(11 * 10^6) * \log_2(11 * 10^6) = (11 * 10^6)\{\log_2(11) + 6\log_2(10)\} = what?$ $(60 * 10^6) * \log_2(60 * 10^6) = (60 * 10^6)\{\log_2(60) + 6\log_2(10)\} = what?$ Then you fill out the rest of the table. Thanks from sita Last edited by skipjack; November 3rd, 2018 at 09:49 AM. November 3rd, 2018, 07:37 AM   #3
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Quote:
 Originally Posted by JeffM1 This is basically just arithmetic. You calculate $\displaystyle \frac{1}{2} * (11 * 10^6)^2 \approx what?$ $\displaystyle \frac{1}{2} * (60 * 10^6)^2 \approx what?$ $(11 * 10^6) * \log_2(11 * 10^6) = (11 * 10^6)\{\log_2(11) + 6\log_2(10)\} = what?$ $(60 * 10^6) * \log_2(60 * 10^6) = (60 * 10^6)\{\log_2(60) + 6\log_2(10)\} = what?$ Then you fill out the rest of the table.
If I did for $n_2$ $\displaystyle \frac{1}{2} * (6 * 10^7)^2 \approx what?$

Would that be right?

Last edited by skipjack; November 3rd, 2018 at 09:51 AM. November 3rd, 2018, 09:36 AM   #4
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 Originally Posted by sita If I did for $n_2$ $\displaystyle \frac{1}{2} * (6 * 10^7)^2 \approx what?$ Would that be right?
Yes.

$\displaystyle 60 * 10^6 = 6 * 10^1 * 10^6 = 6 * 10^{(1 + 6)} = 6 * 10^7 \implies \\ \displaystyle \frac{1}{2} * (60 * 10^6) = \frac{1}{2} * (6 * 10^7) = 3 * 10^7.$

Last edited by skipjack; November 3rd, 2018 at 09:56 AM. Tags algorithms, question Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post sita Computer Science 6 November 2nd, 2018 06:57 PM OriaG Calculus 9 June 8th, 2015 08:13 PM Schoff43 Algebra 2 November 21st, 2014 11:45 PM iKnowAll Computer Science 1 February 7th, 2014 12:16 PM vamsi Number Theory 0 February 25th, 2013 09:35 PM

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