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 January 28th, 2017, 02:57 AM #1 Newbie   Joined: Mar 2016 From: Alabama Posts: 18 Thanks: 0 Another Boolean question Wolfram|Alpha: Computational Knowledge Engine Wolfram|Alpha: Computational Knowledge Engine Why is the first link a tautology and the second not? Why is bringing "(X||Y)&&(X nand Y)" to the front a mistake? (Edit: The forum software automatically put the end url markers at the wrong place. It was confused by all the parentheses.) Last edited by zambod; January 28th, 2017 at 03:01 AM.
 January 29th, 2017, 03:45 AM #2 Senior Member   Joined: Feb 2016 From: Australia Posts: 1,797 Thanks: 633 Math Focus: Yet to find out. Why wouldn't it be? But have you double checked your brackets?
 February 3rd, 2017, 09:58 AM #3 Member   Joined: Feb 2014 Posts: 91 Thanks: 1 A tautology happens when all conditions are true no matter what. Using a truth table you will be able to figure this out.
February 3rd, 2017, 05:43 PM   #4
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Quote:
 Originally Posted by The_Ys_Guy A tautology happens when all conditions are true no matter what. Using a truth table you will be able to figure this out.
I don't think that's what he was asking. And.. 4 input system will give 2^4 output very arduous by hand.

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