|June 10th, 2016, 05:50 PM||#1|
Joined: Jun 2016
question about Unicode
I need help on how to solve this question below.
Question: How many pages of unicode text can a 4 GB storage hold?
The average web page can hold 2000 characters
Must show process of unit conversions.
|June 11th, 2016, 07:18 AM||#2|
Joined: Dec 2012
From: Hong Kong
Math Focus: Linear algebra, linear statistical models
Can we assume 1 character = 8 bits, i.e. UTF-8? (Because Unicode has been extended.)
If so, 4 GB = 4 * 1024 MB = 4 * 1024 * 1024 KB = 4 * 1024 * 1024 * 1024 B
Since each character is 1 B, the storage space can hold 4294967296 characters.
(4294967296 char) / (2000 char/page) = 2147483.648 pages.
|Thread||Thread Starter||Forum||Replies||Last Post|
|I have a question about sine and cosine transform, and the question also includes a H||sCoRPion||Differential Equations||0||March 16th, 2015 01:05 PM|
|Stats question: The Secretary Question word problem||pudro||Algebra||0||November 10th, 2008 09:12 PM|