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February 2nd, 2012, 02:22 AM  #1 
Newbie Joined: Sep 2009 Posts: 9 Thanks: 0  DFA to Regular Expression
Hey, I'm hoping someone can help me understand this. How did (b) become (c)? I'm familiar with the GNFA algorithm, but when I try to get rid of state1 there are too many links that's throwing me off.. Thanks! 
February 2nd, 2012, 08:25 AM  #2  
Global Moderator Joined: Nov 2006 From: UTC 5 Posts: 16,046 Thanks: 937 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms  Re: DFA to Regular Expression Quote:
Then you can contract the loop between 1 and 2 by noticing that it just gives you aa, so each time you go to the state you can get either an aa or a b, any number of times each. Do the same with the loop between 1 and 3. But now you've removed the possibility to go from an (aa or a b) at 2 to a bb at 3, so add those arrows in with what it would take to go between them.  

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