
Computer Science Computer Science Forum 
 LinkBack  Thread Tools  Display Modes 
January 25th, 2012, 04:24 PM  #1 
Joined: Jan 2012 Posts: 6 Thanks: 0  Simple geometry problem with a complex context
I'm working with 3D geometry, and I've been at this for days. I'm beating my head against a wall, because I'm nearly done with the project. There's only one glitch in my system. The Situation: I have a 3D cartesian coordinate system with a Spherical system overlaid over it (the "poles" correspond with the Z axis, so that if you're looking from 90 degrees (polar north) you're looking down the Z axis. I'm writing a computer program that does 3D geometric translations to "move" the points in the coordinate system. The problem: I have MOST of it working. My only problem is when the user does a "translation" after a couple of rotations. So basically, Rotate the coordinate system by N degrees azimuth (at 0 degrees elevation) Do an X, Y translation Rotate the coordinate system back to the previous position Now what was the translation in terms of X,Y,Z coordinates (at the new rotation) Here's the program: http://www.energematrice6.com/gview/index.html Note, the app only works in IE9, Firefox 56+, Google Chrome, Safari, etc ...In order to make it mess up, do the following. Click at the top of the view area and drag to the bottom (rotate from 90 degrees elevation to 0) Click and drag from right to left or left to right a couple of times. (rotates in azimuth) Now right click and drag. (Yes I know the direction it moves is inverted so that you drag left it goes right you drag right it goes left). ...What it's NOT supposed to do is move closer and farther away. In something resembling math language, here is the code I've been using: TXtmp = Amount of X translation TYtmp = Amount of Y translation TZtmp = 0 (there is no Z translation) Cos11 = Cosine of Azimuth Rotation Sin11 = Sine of Azimuth Rotation Cos12 = Cosine of Elevation Rotation Sin12 = Sine of Elevation Rotation TXtmp2 = TXtmp TYtmp2 = TYtmp*Cos12  TZtmp*Sin12 TZtmp2 = TYtmp*Sin12 + TZtmp*Cos12 Final X = TXtmp2*Cos11  TYtmp2*Sin11 Final Y = TXtmp2*Sin11 + TYtmp2*Cos11 Final Z = TZtmp2 The raw code is below: function galFEnd(){ TXtmp = Math.round(pointerX  pointerEndX) TYtmp = Math.round(pointerY  pointerEndY) TZtmp = 0 var Cos11 = Math.cos(Cam1[1]*Math.PI/180) var Sin11 = Math.sin(Cam1[1]*Math.PI/180) var TempAng = Cam[2]Cam1[2] var Cos12 = Math.cos(TempAng*Math.PI/180) var Sin12 = Math.sin(TempAng*Math.PI/180) TXtmp2 = TXtmp TYtmp2 = TYtmp*Cos12  TZtmp*Sin12 TZtmp2 = TYtmp*Sin12 + TZtmp*Cos12 TXtmp3 = TXtmp2*Cos11  TYtmp2*Sin11 TYtmp3 = TXtmp2*Sin11 + TYtmp2*Cos11 TZtmp3 = TZtmp2 //Set the new focus position Cam1[4] = Math.round((Cam1[4] + TXtmp3)/2) Cam1[5] = Math.round((Cam1[5] + TYtmp3)/2) Cam1[6] = Math.round((Cam1[6] + TZtmp3)/2) } 
January 27th, 2012, 02:03 AM  #2  
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 6,586 Thanks: 504 Math Focus: Elementary mathematics and beyond  Re: Simple geometry problem with a complex context Quote:
Also, there is nothing visible in the window from time to time and that can be confusing. Can you provide more background about your application? What is the purpose?  
January 28th, 2012, 12:26 PM  #3 
Joined: Jan 2012 Posts: 6 Thanks: 0  Re: Simple geometry problem with a complex context
Greg, I had never heard of using it that way. https://commons.wikimedia.org/wiki/File ... system.svg That was the orientation I was using. Z toward the user. X horizontal. Y vertical. As to nothing being visible in the window... If it never shows anything, that's a good indication that your browser doesn't support it. I'm using HTML5 Canvas (only supported by chrome, newer versions of firefox, opera, safari and IE9.) If it's just that the "stars" are disappearing from time to time, the application is far from finished, so it's not completely worked out yet. The problem I'm having is basically that I'm trying to do a simple transformation in X,Y,Z based on how the user moves the mouse (with a rightclick). The complication is that everything is based on the original position of the X,Y,Z system, so when the user clicks+drags the screen in a given direction, it has to reversecalculate whatever rotation is on the camera before it applies the x,y,z translation. ... I have to figure out, given the user's current camera rotation (and assuming that X, Y are left/right, up/down respectively at the CURRENT rotation) what the X,Y,Z translation is at the original camera angle. 
January 28th, 2012, 01:06 PM  #4 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 6,586 Thanks: 504 Math Focus: Elementary mathematics and beyond  Re: Simple geometry problem with a complex context
I should have stated usual mathematical standard. I'll see if I can figure something out. 
January 28th, 2012, 02:33 PM  #5 
Joined: Jan 2012 Posts: 6 Thanks: 0  Re: Simple geometry problem with a complex context
Sorry, I don't claim in any way to be proficient at anything other than very basic mathematics. (Algebra and simple geometry). If I was, I'd guess I wouldn't be having so many problems here. :P My latest brainstorm was to try just defining my new "rotation" point on the spherical coordinate system, rotating it, then reconverting the location to cartesian coordinates. It seems to have worked even less spectacularly. function galFEnd(){ TXtmp = Math.round(pointerX  pointerEndX) TYtmp = Math.round(pointerY  pointerEndY) TZtmp = 25//Math.round(Math.sqrt(25*25+TXtmp*TXtmp+TYtmp*TYtmp )) var TempAng = Cam1[2]  Cam[2] TXtmp2 = Math.sqrt(TXtmp*TXtmp + TYtmp*TYtmp + TZtmp*TZtmp) //actually r TYtmp2 = Math.acos(TZtmp/TXtmp2)*180/Math.PI; //actually theta TZtmp2 = Math.atan2(TYtmp,TXtmp)*180/Math.PI; //actually phi var Rtmp = TXtmp2 //r var Ttmp = TYtmp2  TempAng //new theta var Ptmp = TZtmp2  Cam1[1] //new phi var CosP = Math.cos(Ptmp*Math.PI/180) var SinP = Math.sin(Ptmp*Math.PI/180) var CosT = Math.cos(Ttmp*Math.PI/180) var SinT = Math.sin(Ttmp*Math.PI/180) TXtmp3 = Rtmp*SinT*CosP TYtmp3 = Rtmp*SinT*SinP TZtmp3 = Rtmp*CosT Cam1[4] = Math.round(Cam1[4] + TXtmp3) Cam1[5] = Math.round(Cam1[5] + TYtmp3) Cam1[6] = Math.round(Cam1[6] + TZtmp3  25) 
February 9th, 2012, 04:09 PM  #6 
Joined: Jan 2012 Posts: 6 Thanks: 0  Re: Simple geometry problem with a complex context
The answer turned out to be as simple as i thought it was. var Cos11 = Math.cos(Cam1[1]*Math.PI/180) var Sin11 = Math.sin(Cam1[1]*Math.PI/180) should have been var Cos11 = Math.cos(Cam1[1]*Math.PI/180*1) var Sin11 = Math.sin(Cam1[1]*Math.PI/180*1) Don't ask me why or what made the difference, but this fixed it. 
February 9th, 2012, 04:14 PM  #7 
Global Moderator Joined: Nov 2006 From: UTC 5 Posts: 15,255 Thanks: 748 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic  Re: Simple geometry problem with a complex context
Glad to see that worked!


Tags 
complex, context, geometry, problem, simple 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Simple Geometry  clandarkfire  Geometry  3  February 4th, 2012 01:57 PM 
Simple complex conjugate problem  dunn  Complex Analysis  3  January 16th, 2012 03:19 AM 
Two simple solutions for a hard geometry problem  oswaldo  Geometry  10  December 9th, 2009 09:54 PM 
simple geometry Q  tobymac  Geometry  7  July 22nd, 2009 02:55 PM 
Simple Geometry  coolabear  Geometry  1  May 29th, 2008 10:06 AM 