My Math Forum Problem about equivalence

 Complex Analysis Complex Analysis Math Forum

 December 27th, 2014, 08:09 PM #1 Newbie     Joined: Jun 2014 From: Hong Kong Posts: 7 Thanks: 0 Problem about equivalence Suppose we have two equation x1=Ae^iωt + Be^-iωt and x2=A*e^-iωt + B*e^iωt . Where A and B are complex number and A* B* are their conjugate correspondingly. Now if we want to make x1 and x2 exactly equivalent all the time, one way to do it is to have A=B* and B=A* so that x1 and x2 are equivalent. However, if we don't do it by this approach but instead set (A-B*)e^iωt=(A*-B)e^-iωt, then we have e^i2ωt=(A*-B)/(A-B*). I would like to ask if the A and B chosen can satisfy this criteria (even A≠B* and B≠A*), can we still say that x1 ≡ x2 ? Another thing trouble me is if A=B* and B=A* , then e^i2ωt=(A*-B)/(A-B*)=0/0 which is undefined. What causes this problem? Last edited by kelsiu; December 27th, 2014 at 08:12 PM.

 Tags equivalence, problem

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post ChristinaScience Algebra 1 January 25th, 2014 06:33 PM Frenchie. Applied Math 4 January 24th, 2012 09:12 AM julian21 Algebra 3 December 8th, 2011 01:20 PM Nick1978 Applied Math 2 December 16th, 2010 08:21 AM Frenchie. Number Theory 3 December 31st, 1969 04:00 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top