My Math Forum Real part of the complex potential(flow function)

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 September 2nd, 2014, 11:04 AM #1 Newbie   Joined: Sep 2013 Posts: 3 Thanks: 0 Real part of the complex potential(flow function) Hi colleges-mathematicians, just wondering if you could help me solve some tricky staff which I spend a lot of time on, and which kinda stops progress on my assignment Find the real part (velocity potential) of the complex potential: f(z)=-0.5*z*sqrt(a^2-z^2)+i(-0.5*z^2) Thanx!!!
 September 3rd, 2014, 02:34 AM #2 Senior Member   Joined: Apr 2014 From: Glasgow Posts: 2,133 Thanks: 719 Math Focus: Physics, mathematical modelling, numerical and computational solutions Taking the real part just means ignoring all terms with $\displaystyle i$ in them, so the real part of $\displaystyle f(z) = \frac{z}{2}\sqrt{a^2-z^2} - \frac{1}{2}i(z^2)$ is $\displaystyle Re\{f(z)\} = \frac{1}{2}z\sqrt{a^2-z^2}$ If $\displaystyle z$ is complex you have to substitute it in first before making this step.
September 3rd, 2014, 03:19 AM   #3
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 Originally Posted by Benit13 Taking the real part just means ignoring all terms with $\displaystyle i$ in them, so the real part of $\displaystyle f(z) = \frac{z}{2}\sqrt{a^2-z^2} - \frac{1}{2}i(z^2)$ is $\displaystyle Re\{f(z)\} = \frac{1}{2}z\sqrt{a^2-z^2}$ If $\displaystyle z$ is complex you have to substitute it in first before making this step.

Sorry, i have forgotten to define z, it s a complex number, which makes it kinda difficult to split the f function:
z=x + i*y

Last edited by Bogdano; September 3rd, 2014 at 03:23 AM.

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