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November 5th, 2008, 07:05 AM  #1 
Newbie Joined: Oct 2008 Posts: 2 Thanks: 0  Finding roots of a complex numbers equation
I cant seem to fully figure a problem like this one out. How is it done? z^5z^4+(1j)z+(j1)=0 Thanks 
November 5th, 2008, 02:19 PM  #2  
Global Moderator Joined: May 2007 Posts: 6,416 Thanks: 558  Re: Finding roots of a complex numbers equation Quote:
 
November 6th, 2008, 09:52 AM  #3 
Newbie Joined: Oct 2008 Posts: 10 Thanks: 0  Re: Finding roots of a complex numbers equation
z^5z^4+(1j)z+(j1)=0 goes in this way: z^4 (z1) + (1j)z  (1j) = 0 <=> z^4 (z1) + (1j) (z1) = 0 <=> and then factorize (z1) hence the (z1) (z^4+1j) = 0 then z= 1 OR z^4=1+j (...) now it is pretty easy. (z^4 must have only 4 roots. put it in polar form and it's done!) 

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complex, equation, finding, numbers, roots 
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