
Complex Analysis Complex Analysis Math Forum 
 LinkBack  Thread Tools  Display Modes 
November 5th, 2008, 06:05 AM  #1 
Newbie Joined: Oct 2008 Posts: 2 Thanks: 0  Finding roots of a complex numbers equation
I cant seem to fully figure a problem like this one out. How is it done? z^5z^4+(1j)z+(j1)=0 Thanks 
November 5th, 2008, 01:19 PM  #2  
Global Moderator Joined: May 2007 Posts: 6,496 Thanks: 577  Re: Finding roots of a complex numbers equation Quote:
 
November 6th, 2008, 08:52 AM  #3 
Newbie Joined: Oct 2008 Posts: 10 Thanks: 0  Re: Finding roots of a complex numbers equation
z^5z^4+(1j)z+(j1)=0 goes in this way: z^4 (z1) + (1j)z  (1j) = 0 <=> z^4 (z1) + (1j) (z1) = 0 <=> and then factorize (z1) hence the (z1) (z^4+1j) = 0 then z= 1 OR z^4=1+j (...) now it is pretty easy. (z^4 must have only 4 roots. put it in polar form and it's done!) 

Tags 
complex, equation, finding, numbers, roots 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Chracteristic eq, finding complex roots  goldtooth  Linear Algebra  9  December 30th, 2013 10:38 AM 
Finding roots (complex numbers)  TsAmE  Complex Analysis  4  October 19th, 2010 08:48 PM 
Finding Polynomial with Roots of Real and Complex Numbers  HFH  Algebra  3  May 29th, 2010 01:19 PM 
Finding complex numbers that solves equation  tach  Complex Analysis  3  December 13th, 2009 06:51 AM 
roots of a complex equation  slade8200  Complex Analysis  1  February 20th, 2009 08:34 AM 