May 8th, 2014, 04:30 AM |
#1 |

Newbie Joined: May 2014 From: Pune Posts: 2 Thanks: 0 | How to Solve this?
On Simplification, [i^19 + (1/25)^25]^2 becomes (a) -4 (b) 4-1 (c) 2+i (d) None Of the above |

May 8th, 2014, 05:34 AM |
#2 |

Senior Member Joined: Apr 2014 From: UK Posts: 965 Thanks: 342 |
d let x= i^19, y = (1/25)^25 [x + y]^2 x^2 + 2xy + y^2 The y^2 bit is going to be a very small number The 2xy bit is a bunch of i The x^2 bit is -1 Add those and it can't be a,b or c |