My Math Forum complex plane

 Complex Analysis Complex Analysis Math Forum

 June 8th, 2019, 02:12 AM #1 Newbie   Joined: Jun 2019 From: Ukraine Posts: 6 Thanks: 0 complex plane Hello to all. I am new and I need your help. Task: Build an area on the complex plane - | z + 1 | > | 1 - z | Last edited by skipjack; June 8th, 2019 at 03:25 AM.
 June 8th, 2019, 03:31 AM #2 Global Moderator   Joined: Dec 2006 Posts: 20,966 Thanks: 2216 Let P be the point in the complex plane corresponding to z. The inequality holds if and only if P is closer to the point (1, 0) than to the point (-1, 0). P is equidistant from (1, 0) and (0, 1) if and only if P lies on the imaginary axis. Can you proceed from there?
 June 8th, 2019, 03:39 AM #3 Newbie   Joined: Jun 2019 From: Ukraine Posts: 6 Thanks: 0 I don't quite understand how to plot
 June 8th, 2019, 05:03 AM #4 Global Moderator   Joined: Dec 2006 Posts: 20,966 Thanks: 2216 How to plot what?
 June 8th, 2019, 05:24 AM #5 Newbie   Joined: Jun 2019 From: Ukraine Posts: 6 Thanks: 0 how to build a graph?
 June 8th, 2019, 05:38 AM #6 Global Moderator   Joined: Dec 2006 Posts: 20,966 Thanks: 2216 I wasn't sure what "build an area" meant. The inequality is satisfied if and only if Re(z) > 0.
 June 8th, 2019, 05:49 AM #7 Newbie   Joined: Jun 2019 From: Ukraine Posts: 6 Thanks: 0 As I understood you need to build a graph in the complex plane of this inequality.
June 8th, 2019, 05:57 AM   #8
Newbie

Joined: Jun 2019
From: Ukraine

Posts: 6
Thanks: 0

I think this is correct but how to do it
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