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June 8th, 2019, 02:12 AM   #1
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Question complex plane

Hello to all. I am new and I need your help.
Task: Build an area on the complex plane - | z + 1 | > | 1 - z |

Last edited by skipjack; June 8th, 2019 at 03:25 AM.
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June 8th, 2019, 03:31 AM   #2
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Let P be the point in the complex plane corresponding to z.

The inequality holds if and only if P is closer to the point (1, 0) than to the point (-1, 0).

P is equidistant from (1, 0) and (0, 1) if and only if P lies on the imaginary axis.

Can you proceed from there?
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June 8th, 2019, 03:39 AM   #3
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I don't quite understand how to plot
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June 8th, 2019, 05:03 AM   #4
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How to plot what?
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June 8th, 2019, 05:24 AM   #5
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how to build a graph?
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June 8th, 2019, 05:38 AM   #6
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I wasn't sure what "build an area" meant. The inequality is satisfied if and only if Re(z) > 0.
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June 8th, 2019, 05:49 AM   #7
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As I understood you need to build a graph in the complex plane of this inequality.
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June 8th, 2019, 05:57 AM   #8
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I think this is correct but how to do it
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