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May 6th, 2019, 07:26 AM  #11  
Math Team Joined: Jul 2011 From: Texas Posts: 3,002 Thanks: 1587  Quote:
 
May 10th, 2019, 09:11 AM  #12 
Member Joined: Aug 2018 From: România Posts: 84 Thanks: 6 
Hello all, Solving the WolframAlpha computing program: https://www.wolframalpha.com/input/?...%2B2%7C%27%3D0  The first two solutions given by "WolframAlpha" are the same as those found by me. From my calculations would also result solutions for $\displaystyle k(a)=0$ , $\displaystyle k(a)=i(a2)$ , $\displaystyle k(a)=i(a1)$ and $\displaystyle k(a)=\frac{i(2a3)}{2}$ where $\displaystyle i^2=1$ , $\displaystyle a=Re(x)$ and $\displaystyle k(a)=Im(x)$ , but I do not know how to interpret them to calculate $\displaystyle x=a+k(a)i$ .... All the best, Integrator Last edited by Integrator; May 10th, 2019 at 09:34 AM. 

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equation, modules, modulus 
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