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December 26th, 2018, 03:20 PM   #1
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Finding the roots of a 6-degree polynomial

Hello,
I am having trouble finding the roots of a 6-degree polynomial equation in expression form. I hope anyone can help reduce it to a form where the expression for each root can be determine.

[IMG]D:\equation.png[/IMG]


Thanks,
ZeroKool
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Last edited by ZeroKool007; December 26th, 2018 at 03:23 PM.
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December 26th, 2018, 03:32 PM   #2
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Quote:
Originally Posted by ZeroKool007 View Post
Hello,
I am having trouble finding the roots of a 6-degree polynomial equation in expression form. I hope anyone can help reduce it to a form where the expression for each root can be determine.

[IMG]D:\equation.png[/IMG]


Thanks,
ZeroKool
This is not a sixth degree polynomial. The coefficients themselves seem to depend on x. After you multiply both sides by $\displaystyle Qx^2 (mx-1)^2$ and simplify, you'll have a 10th degree polynomial.

-Dan
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December 26th, 2018, 05:09 PM   #3
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Dan,
Thanks for the reply... Qx amd mx are defined values, Fx is the variable. Fx^6 and Fx^2 are the degree polynomial...Fx^5, Fx^4, Fx^3, Fx^1 are multiply by 0.

Example: mx=6.3, Qx=0.4 ... this would give the results of
A = 0.4890380
B = 0.788825-0.86129i
C = 0.788825+0.86129i

What I really need is the expression equations for A, B, C.

ZeroKool

Last edited by ZeroKool007; December 26th, 2018 at 05:18 PM.
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