My Math Forum Finding the roots of a 6-degree polynomial

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December 26th, 2018, 03:20 PM   #1
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Finding the roots of a 6-degree polynomial

Hello,
I am having trouble finding the roots of a 6-degree polynomial equation in expression form. I hope anyone can help reduce it to a form where the expression for each root can be determine.

[IMG]D:\equation.png[/IMG]

Thanks,
ZeroKool
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Last edited by ZeroKool007; December 26th, 2018 at 03:23 PM.

December 26th, 2018, 03:32 PM   #2
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Quote:
 Originally Posted by ZeroKool007 Hello, I am having trouble finding the roots of a 6-degree polynomial equation in expression form. I hope anyone can help reduce it to a form where the expression for each root can be determine. [IMG]D:\equation.png[/IMG] Thanks, ZeroKool
This is not a sixth degree polynomial. The coefficients themselves seem to depend on x. After you multiply both sides by $\displaystyle Qx^2 (mx-1)^2$ and simplify, you'll have a 10th degree polynomial.

-Dan

 December 26th, 2018, 05:09 PM #3 Newbie   Joined: Dec 2018 From: USA Posts: 2 Thanks: 0 Dan, Thanks for the reply... Qx amd mx are defined values, Fx is the variable. Fx^6 and Fx^2 are the degree polynomial...Fx^5, Fx^4, Fx^3, Fx^1 are multiply by 0. Example: mx=6.3, Qx=0.4 ... this would give the results of A = 0.4890380 B = 0.788825-0.86129i C = 0.788825+0.86129i What I really need is the expression equations for A, B, C. ZeroKool Last edited by ZeroKool007; December 26th, 2018 at 05:18 PM.

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