 My Math Forum Finding the roots of a 6-degree polynomial
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December 26th, 2018, 03:20 PM   #1
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Finding the roots of a 6-degree polynomial

Hello,
I am having trouble finding the roots of a 6-degree polynomial equation in expression form. I hope anyone can help reduce it to a form where the expression for each root can be determine.

[IMG]D:\equation.png[/IMG]

Thanks,
ZeroKool
Attached Images equation.jpg (21.4 KB, 11 views)

Last edited by ZeroKool007; December 26th, 2018 at 03:23 PM. December 26th, 2018, 03:32 PM   #2
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Quote:
 Originally Posted by ZeroKool007 Hello, I am having trouble finding the roots of a 6-degree polynomial equation in expression form. I hope anyone can help reduce it to a form where the expression for each root can be determine. [IMG]D:\equation.png[/IMG] Thanks, ZeroKool
This is not a sixth degree polynomial. The coefficients themselves seem to depend on x. After you multiply both sides by $\displaystyle Qx^2 (mx-1)^2$ and simplify, you'll have a 10th degree polynomial.

-Dan December 26th, 2018, 05:09 PM #3 Newbie   Joined: Dec 2018 From: USA Posts: 2 Thanks: 0 Dan, Thanks for the reply... Qx amd mx are defined values, Fx is the variable. Fx^6 and Fx^2 are the degree polynomial...Fx^5, Fx^4, Fx^3, Fx^1 are multiply by 0. Example: mx=6.3, Qx=0.4 ... this would give the results of A = 0.4890380 B = 0.788825-0.86129i C = 0.788825+0.86129i What I really need is the expression equations for A, B, C. ZeroKool Last edited by ZeroKool007; December 26th, 2018 at 05:18 PM. Tags 6degree, finding, polynomial, roots Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post ibilal Calculus 3 December 7th, 2011 06:38 AM HFH Algebra 3 May 29th, 2010 01:19 PM TTB3 Abstract Algebra 3 March 8th, 2009 07:57 AM domaPL Real Analysis 1 January 12th, 2008 10:28 AM domaPL Number Theory 0 December 31st, 1969 04:00 PM

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