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February 5th, 2018, 07:41 PM   #1
HAC
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Complex Analysis - Show F(z) is not continuous

I need help with the attached question.

q4.jpg
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February 6th, 2018, 12:20 AM   #2
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Well, what do you get if you do the integration??
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February 6th, 2018, 04:32 AM   #3
HAC
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@micrm i m not sure. can u help me out please
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February 6th, 2018, 03:52 PM   #4
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so you have tried nothing and are all out of ideas then.
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February 6th, 2018, 04:44 PM   #5
HAC
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@SDK i tried f(z)= z bar (complex conjugate of z)

then, for |z|=1, F(z)=z bar

but i do not know what happens when |z|<1. i dont understand how to handle the integral
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